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I am trying to make SEO friendly URLs of using apache mod_rewrite. My normal URLs is something like this - index.php?p=about index.php?p=contact index.php?p=this My expecting SEO friendly URLs should be something similar to this - localhost/php_advance/ch02/about localhost/php_advance/ch02/contact localhost/php_advance/ch02/this I tried it with creating a .htaccess file and doing some changes to my apache httpd.conf file. This is my .htaccess file <ifModule mod_rewrite.c> # Turn on the engine: RewriteEngine on # Set the base to this directory: RewriteBase /php_advance/ch02/ # Redirect certain paths to index.php: RewriteRule ^(about|contact|this|that|search)/?$ index.php?p=$1 </ifModule> And also, At the end of the httpd.conf file, I added some code like this - <Directory "C:/wamp/www/php_advance/ch02"> AllowOverride All </Directory> NOTE: I am using WAMP server and Windows 07 But this coding is not working for me. Hope someone will help me out. Thank you.

I have modified form_functions.inc.php to radio button for suit for me. But It seems its not working.. This is my code so far.. from form function if (preg_match('/sex\d{1}$/', $name)) { $i = substr($name, -1); $name = substr($name, 0, 3); $sex = array(1=>'Male', 'Female' ); // Display the error first: if (array_key_exists($name, $errors)) { echo ' <span class="inline-error">' . $errors[$name] . "</span>\n"; } echo '<input type="' . $type . '" name="' . $name . '" value="' . $i . '" /> ' . $sex[$i] . ' '; } This is from validation code.. // Check for gender: $sex = array(); for ($i=1, $count=2; $i <= $count; $i++) { if (isset($_POST['sex'. $i])) { $sex[] = $_POST['sex'. $i]; } } // end for loop if (empty($sex)){ $reg_errors['sex1'] = 'You have NOT entered your gender type!'; } This from HTML <div class="last-child"> <?php for ($i=1, $count=2; $i <= $count; $i++) { create_form_input('sex' . $i, 'radio', $reg_errors); } ?> </div> radio button working.. but validation not working its always going to error message.. hope someone help me out this.. thank you.

Hello... I have a form to get some urls from users. Eg: Web Address, Facebook Address, Twitter Address, Google+ address etc... My problem is how I validate these urls when they submit the form. I tried to validate URL in PHP by using the FILTER_VALIDATE_URL or simply, using regular expression. Here, I would like to know what are the best methods to get such a urls from users. Is it always good to let them to enter protocol? sometimes they may not know it is http, https, ftp, ftps.. etc. I think it is something hard to do some users. I tried something like this using FILTER_VALIDATE_URL, But it always use protocol and sometime I am confusing how its work.. // validate url $url = '[url="http://www.example.com%27;"]http://www.example.com';[/url] if (filter_var( $url, FILTER_VALIDATE_URL)){ echo "<br>valid"; } else { echo "<br>invalid"; } [b]OUTPUT[/b] : valid // validate url $url = 'hp://www.example.com'; if (filter_var( $url, FILTER_VALIDATE_URL)){ echo "<br>valid"; } else { echo "<br>invalid"; } [b]OUTPUT[/b] : valid // validate url $url = 'http://example.com'; if (filter_var( $url, FILTER_VALIDATE_URL)){ echo "<br>valid"; } else { echo "<br>invalid"; } [b]OUTPUT[/b]: valid // validate url $url = 'http://example.com?id=32&name=kamalani'; if (filter_var( $url, FILTER_VALIDATE_URL)){ echo "<br>valid"; } else { echo "<br>invalid"; } [b]OUTPUT[/b] : valid Can you tell me what are the best ways to get urls from user and how those validate? Any comments are greatly appreciating.. Thank you.

ok.. thanks you. also I would like to know is there another way to get the same result using HTML table format like I posted above?

Thanks for your sugestion. But can you tell me..How can I get <li> items into 2 columns?

Thank you HartleySan... this is a link for a image.. http://www.freeimagehosting.net/6sfhz I think you will get an idea actually what I am going to do whit this.. thanks again...

Oops.... My image is not displaying wiht my post.. can you please tell me how can I attach an image with this post...? I tried to find an option but fail to find.

this is a screan shot showing actually what I am tring to do is... Each category has its own subjects and those subjects need to display in a table with 2 columns.

thanks for reply.. SQL return the values properly...there are category_id, category_name, subject_id, subject_name. I have started the session properly in my configuration file and have included to this page. I am trying to display above return data into a list something like this.. Catagory 01 subjects1 subjects4 subjects2 subjects5 subjects3 subjects6 Catagory 02 subjects1 subjects4 subjects2 subjects5 subjects3 subjects6 Catagory 03 subjects1 subjects4 subjects2 subjects5 subjects3 subjects6 I tried to do it like this. Its working as 50%. But I need to display subjects under each categories in a table with 2 columns. $catID = false; while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) { echo '<div>'; if ( $catID != $row['ci']) { echo '<h3>Category 01: <span>' . $row['cn'] . '</span><span></span></h3>'; } echo '<div class="container">'; echo '<p>' . $row['sn']. '</p>'; // This subjects I need to display in a table with 2 columns.. $catID = $row['ci']; echo '</div>'; echo '</div>'; } The problem I face is, when I am tring to add the subjects into a table.. This is my HTML design.. <div> <h3>Category 01: <span>Information Technology</span><span></span></h3> <div class="container"> <table> <tr> <td width="50%"> <input type="checkbox" value="1" name="category[]">Subject1 </td> <td width="50%"> <input type="checkbox" value="2" name="category[]">Subject4 </td> </tr> <tr> <td width="50%"> <input type="checkbox" value="1" name="category[]">Subject2 </td> <td width="50%"> <input type="checkbox" value="2" name="category[]">Subject5 </td> </tr> <tr> <td width="50%"> <input type="checkbox" value="1" name="category[]">Subject3 </td> <td width="50%"> <input type="checkbox" value="2" name="category[]">Subject6 </td> </tr> </table> </div> </div>

I am going to create a HTML form dynamically with php. Using that form users can select subjects under different category. A category and Its subjects have broken to one logical section and have applied jquery accordion. In my form I need to create more logical section like that. this is the HTML structure of the form..(which need to create dynamically with php) <form action="" method="post"> <div id="accordion"> <!-- logical section 1 --> <div> <h3>Category 01: <span>category name</span><span></span></h3> <div class="container"> <table> <tr> <td width="50%"> <input type="checkbox" value="1" name="subject[]">subject1 </td> <td width="50%"> <input type="checkbox" value="2" name="subject[]">subject2 </td> </tr> </table> </div> </div> <!-- logical section 2 --> <div> <h3>Category 02: <span>category name</span><span></span></h3> <div class="container"> <table> <tr> <td width="50%"> <input type="checkbox" value="1" name="subject[]">subject1 </td> <td width="50%"> <input type="checkbox" value="2" name="subject[]">subject2 </td> </tr> </table> </div> </div> </div> </form> Can anybody tell my where I am going wrong? I troubled how to create inner table with 2 columns.

Thanks for all answers.... I got a solution using IN() in mysql... thanks again..

thanx for response. My table is institute_images and it has image_id, image_name, image_type, institute_id coloumns. designation array's values I use for image_type values. In my query I need to check is there any images in db with image_type value is one of my designation array's value.

I have read it half. (till 7 chapter) .. why is it??

hi.. everyone.. This is a sql query problem that I have uncounted and have been in the same script for hours. But Still I couldn't get it to work. I need to get a image from database and its type should be one of a value from my $designation array. The query should check $designation array's value with database and if its match with one of a value in database then query can retrieve one row. This is my designation array. its value I use for image type in my db. $designation = array ( 'Managing Director', 'Manager', 'Director', 'The Principal', 'Deputy Principal', 'Proprietor', 'Assistant Manager', 'Head Master'); My problem is how can I check these value exit in my table and how can I make a query for this. In query where condition is confusing to me... any comments are greatly appreciated. Thank you..

Yes.. I used tutor_institute directory and sometimes used lanka_institute directory too for experiments porpose. when I use both directories I did it correctly in my htaccess and browser url. But still I couldn't it to get working. actually what has happend there... I followed more online tutorials to subject and all of them are fomfort for me. but I cant get it work in my project... any comments are greatly appreciated. Thank you..