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I am trying to make SEO friendly URLs of using apache mod_rewrite. My normal URLs is something like this - index.php?p=about index.php?p=contact index.php?p=this My expecting SEO friendly URLs should be something similar to this - localhost/php_advance/ch02/about localhost/php_advance/ch02/contact localhost/php_advance/ch02/this I tried it with creating a .htaccess file and doing some changes to my apache httpd.conf file. This is my .htaccess file <ifModule mod_rewrite.c> # Turn on the engine: RewriteEngine on # Set the base to this directory: RewriteBase /php_advance/ch02/ # Redirect certain paths to index.php: RewriteRule ^(about|contact|this|that|search)/?$ index.php?p=$1 </ifModule> And also, At the end of the httpd.conf file, I added some code like this - <Directory "C:/wamp/www/php_advance/ch02"> AllowOverride All </Directory> NOTE: I am using WAMP server and Windows 07 But this coding is not working for me. Hope someone will help me out. Thank you.

I have modified form_functions.inc.php to radio button for suit for me. But It seems its not working.. This is my code so far.. from form function if (preg_match('/sex\d{1}$/', $name)) { $i = substr($name, -1); $name = substr($name, 0, 3); $sex = array(1=>'Male', 'Female' ); // Display the error first: if (array_key_exists($name, $errors)) { echo ' <span class="inline-error">' . $errors[$name] . "</span>\n"; } echo '<input type="' . $type . '" name="' . $name . '" value="' . $i . '" /> ' . $sex[$i] . ' '; } This is from validation code.. // Check for gender: $sex = array(); for ($i=1, $count=2; $i <= $count; $i++) { if (isset($_POST['sex'. $i])) { $sex[] = $_POST['sex'. $i]; } } // end for loop if (empty($sex)){ $reg_errors['sex1'] = 'You have NOT entered your gender type!'; } This from HTML <div class="last-child"> <?php for ($i=1, $count=2; $i <= $count; $i++) { create_form_input('sex' . $i, 'radio', $reg_errors); } ?> </div> radio button working.. but validation not working its always going to error message.. hope someone help me out this.. thank you.

Hello... I have a form to get some urls from users. Eg: Web Address, Facebook Address, Twitter Address, Google+ address etc... My problem is how I validate these urls when they submit the form. I tried to validate URL in PHP by using the FILTER_VALIDATE_URL or simply, using regular expression. Here, I would like to know what are the best methods to get such a urls from users. Is it always good to let them to enter protocol? sometimes they may not know it is http, https, ftp, ftps.. etc. I think it is something hard to do some users. I tried something like this using FILTER_VALIDATE_URL, But it always use protocol and sometime I am confusing how its work.. // validate url $url = '[url="http://www.example.com%27;"]http://www.example.com';[/url] if (filter_var( $url, FILTER_VALIDATE_URL)){ echo "<br>valid"; } else { echo "<br>invalid"; } [b]OUTPUT[/b] : valid // validate url $url = 'hp://www.example.com'; if (filter_var( $url, FILTER_VALIDATE_URL)){ echo "<br>valid"; } else { echo "<br>invalid"; } [b]OUTPUT[/b] : valid // validate url $url = 'http://example.com'; if (filter_var( $url, FILTER_VALIDATE_URL)){ echo "<br>valid"; } else { echo "<br>invalid"; } [b]OUTPUT[/b]: valid // validate url $url = 'http://example.com?id=32&name=kamalani'; if (filter_var( $url, FILTER_VALIDATE_URL)){ echo "<br>valid"; } else { echo "<br>invalid"; } [b]OUTPUT[/b] : valid Can you tell me what are the best ways to get urls from user and how those validate? Any comments are greatly appreciating.. Thank you.

ok.. thanks you. also I would like to know is there another way to get the same result using HTML table format like I posted above?

Thanks for your sugestion. But can you tell me..How can I get <li> items into 2 columns?

Thank you HartleySan... this is a link for a image.. http://www.freeimagehosting.net/6sfhz I think you will get an idea actually what I am going to do whit this.. thanks again...

Oops.... My image is not displaying wiht my post.. can you please tell me how can I attach an image with this post...? I tried to find an option but fail to find.

this is a screan shot showing actually what I am tring to do is... Each category has its own subjects and those subjects need to display in a table with 2 columns.

thanks for reply.. SQL return the values properly...there are category_id, category_name, subject_id, subject_name. I have started the session properly in my configuration file and have included to this page. I am trying to display above return data into a list something like this.. Catagory 01 subjects1 subjects4 subjects2 subjects5 subjects3 subjects6 Catagory 02 subjects1 subjects4 subjects2 subjects5 subjects3 subjects6 Catagory 03 subjects1 subjects4 subjects2 subjects5 subjects3 subjects6 I tried to do it like this. Its working as 50%. But I need to display subjects under each categories in a table with 2 columns. $catID = false; while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) { echo '<div>'; if ( $catID != $row['ci']) { echo '<h3>Category 01: <span>' . $row['cn'] . '</span><span></span></h3>'; } echo '<div class="container">'; echo '<p>' . $row['sn']. '</p>'; // This subjects I need to display in a table with 2 columns.. $catID = $row['ci']; echo '</div>'; echo '</div>'; } The problem I face is, when I am tring to add the subjects into a table.. This is my HTML design.. <div> <h3>Category 01: <span>Information Technology</span><span></span></h3> <div class="container"> <table> <tr> <td width="50%"> <input type="checkbox" value="1" name="category[]">Subject1 </td> <td width="50%"> <input type="checkbox" value="2" name="category[]">Subject4 </td> </tr> <tr> <td width="50%"> <input type="checkbox" value="1" name="category[]">Subject2 </td> <td width="50%"> <input type="checkbox" value="2" name="category[]">Subject5 </td> </tr> <tr> <td width="50%"> <input type="checkbox" value="1" name="category[]">Subject3 </td> <td width="50%"> <input type="checkbox" value="2" name="category[]">Subject6 </td> </tr> </table> </div> </div>

I am going to create a HTML form dynamically with php. Using that form users can select subjects under different category. A category and Its subjects have broken to one logical section and have applied jquery accordion. In my form I need to create more logical section like that. this is the HTML structure of the form..(which need to create dynamically with php) <form action="" method="post"> <div id="accordion"> <!-- logical section 1 --> <div> <h3>Category 01: <span>category name</span><span></span></h3> <div class="container"> <table> <tr> <td width="50%"> <input type="checkbox" value="1" name="subject[]">subject1 </td> <td width="50%"> <input type="checkbox" value="2" name="subject[]">subject2 </td> </tr> </table> </div> </div> <!-- logical section 2 --> <div> <h3>Category 02: <span>category name</span><span></span></h3> <div class="container"> <table> <tr> <td width="50%"> <input type="checkbox" value="1" name="subject[]">subject1 </td> <td width="50%"> <input type="checkbox" value="2" name="subject[]">subject2 </td> </tr> </table> </div> </div> </div> </form> Can anybody tell my where I am going wrong? I troubled how to create inner table with 2 columns.

Thanks for all answers.... I got a solution using IN() in mysql... thanks again..

thanx for response. My table is institute_images and it has image_id, image_name, image_type, institute_id coloumns. designation array's values I use for image_type values. In my query I need to check is there any images in db with image_type value is one of my designation array's value.

I have read it half. (till 7 chapter) .. why is it??

hi.. everyone.. This is a sql query problem that I have uncounted and have been in the same script for hours. But Still I couldn't get it to work. I need to get a image from database and its type should be one of a value from my $designation array. The query should check $designation array's value with database and if its match with one of a value in database then query can retrieve one row. This is my designation array. its value I use for image type in my db. $designation = array ( 'Managing Director', 'Manager', 'Director', 'The Principal', 'Deputy Principal', 'Proprietor', 'Assistant Manager', 'Head Master'); My problem is how can I check these value exit in my table and how can I make a query for this. In query where condition is confusing to me... any comments are greatly appreciated. Thank you..

Yes.. I used tutor_institute directory and sometimes used lanka_institute directory too for experiments porpose. when I use both directories I did it correctly in my htaccess and browser url. But still I couldn't it to get working. actually what has happend there... I followed more online tutorials to subject and all of them are fomfort for me. but I cant get it work in my project... any comments are greatly appreciated. Thank you..

I change .htaccess file like this RewriteEngine on RewriteBase tutor_institute/profiles/tutors/ RewriteUrl ^test.html index.php Create test.html file and placed it in tutors sub directory which is my index.php file exist. typed url in address bar, its like this http://localhost/lanka_institute/profiles/tutors/test.html Now I can get this massege in browser window. page title display where I am going wrong???? Thank you

Actually I cant understand what I need to do with your answer. sorry for my little knowledge of the subject. Any way I change my .htaccess file like this RewriteEngine on RewriteBase tutor_institute/profiles/tutors/ RewriteRule ^/profiles/tutors/([0-9]+)/([A-Za-z_]+)/([A-Za-z_]+)$ index.php?tutorCode=$1&tutorName=$2&city=$3 [NC] but nothing happen.. if you can elaborate your solution, It will help me understand the subjects. any comments are greatly appreciated. thank you.

thanks for response... I am not going to redirect to another domain. sorry for my incomplete and unclear question. actually Im going to do is a dynamically generated url convert to frienly url. this is php generated url.. http://localhost/tutor_institute/profiles/tutors/index.php?tutorCode=1255&tutorName=Jhon Amarathunga&city=Perth I need to rewrite it like this http://localhost/tutor_institute/profiles/tutors/1255/Perth/Jhon Amarathunga.html My index.php page dynamically generate more teacher's profile in my website. Thats why I need to rewrite that url to a friendly format. the path to my index.php file from the server's root directory is 'tutor_institute/profiles/tutors/index.php' tutor_institute,profiles and tutors are sub folders in my root directory. In my home page there are links to all tutor profiles generated by system. It link is something like this.. echo '<h2><a href="profiles/tutors/index.php?tutorCode=' . $row3['tutor_code'] . '&tutorName=' . $row3['tutor_name'] . '&city=' . $row3['city_name'] . '">' . $row3['tutor_name'] . '</a></h2>'; This is from my .htaccess file and I have placed .htaccess file in to 'tutors' sub directory which contain my index.php file. RewriteEngine on RewriteRule ^/profiles/tutors/([0-9]+)/([A-Za-z_]+)/([A-Za-z_]+)$ index.php?tutorCode=$1&tutorName=$2&city=$3 [NC] Thank you

Thank you Mr. Larry for your quick response. Its greatly appreciated.

hello... everyone.. I have some small problem. It is when Im fetch data from my database and print those in different location. I have a database to store images and it contain many type of images. Eg. gallery image, comments image, ad image and so on. So now I need to get only images which type is 'ad'. Note: A single user can store only 2 images as ad images. That mean there are two ad images to a particular user. It ok for me. I did it like this. $q = "SELECT image_name FROM images WHERE image_type = 'ad' AND user = $id"; $r = mysqli_query( $dbc, $q ); while ( $row = mysqli_fetch_array( $r, MYSQLI_ASSOC)) { $imageName = $row['image_name']; $imageName; // two images contain in this variable. } My problem is, can anybody say, is there a way to print those 2 images in different location (in different two DIV ) and out of while loop. Eg: <div class="add1"> image1 </div> <div class="add2"> image2 </div> any comments are highly appreciated. thank you.

hi.. everyone.. I need to rewrite this URL http://localhost/lanka_institute/profiles/tutors/index.php?tutorCode=1255&tutorName=Kasun%20Perera&city=Bandarawela like this http://www.mydomain.com/profiles/tutors/1255/Kasun+Perera.html I tried this with Apache’s mod_rewrite feature. But I couldn't reach to my expecting result. Here is Code that I have tried. <IfModule mod_rewrite.c> RewriteEngine on # For specific teachers: RewriteRule ^localhost/lanka_institute/profiles/tutors/([0-9]+)/([A-Za-z\+\-]+)/([A-Za-z\+\-]+)/$ index.php?tutorCode=$1&tutorName=$2&city=$3 </IfModule> It is not working and then I can get this error message. any comments are greatly appreciated. Thank you.

Hello... I am some confuse with this matter. I want to print a order list with a title in php. those come from my database. Title is my category name and order list should be my subjects. I used 'institute_category_subject' table and i contain all institutes, categories and their subjects. something like this... I now need to create my list with these values. It is something like this.. +--------+--------------+-------------+------------+ | ics_id | institute_id | category_id | subject_id | +--------+--------------+-------------+------------+ | 1 | 1 | 1 | 2 | | 2 | 1 | 1 | 4 | | 3 | 1 | 2 | 2 | | 4 | 1 | 2 | 3 | | 5 | 1 | 3 | 1 | | 6 | 1 | 3 | 4 | +--------+--------------+-------------+------------+ category_name1 sub1 sub2 sub3 category_name2 sub1 sub2 sub3 and so on.... My problem is category id with same value going on many rows in the table and when i retrieve that id and when try to print, same category name printing repeatedly. I need to print my category name at only one time as my title and then need to print their subjects as a order list. any comments are highly appreciated. thank you..

Thank you margaux... It working properly as I expect. But this code is hard to understand.... if (preg_match('/group\d{1}$/', $name)) { $i = substr($name, -1); $groupVal = array(1=>'Individual', 'Small Groups &nbsp;<small>( Below 10 )</small>', 'Medium Groups &nbsp;<small>( Between 10 to 20 )</small>', 'Big Groups &nbsp;<small>( Over 20 )</small>', 'Online Tuition'); // Display the error first: if (array_key_exists($name, $errors)) echo ' <span class="error">' . $errors[$name] . '</span>'; echo '<input type="' . $type . '" name="' . $name . '" value="' . $i . '" class="checkbox" />&nbsp; ' . $groupVal[$i] . '<br />'; } } can you explain how it works.... and If I use select box in a form how can I display error massege like that.... further A select box display in the page with database values.. any comments are highly appreciated.... thank you..

thanks for response.... but I am bit confusing with your answer. If u show me it through an example It will help me. further If u can, tell me what are the thing I have made mistake in my scripts.... Thank you.

Hello...everyone... In my registration form I need to add some check boxes to select more than 1 option about teachers' class option. Larry's Effortless E-Commerce with PHP and MySQL book teach us how to use form input function for text, password and taxtarea inputs. So I modified the function for my check boxes. there I need to display a error message in my registration form when a user not select at least one option from the teacher option check boxes in my register page. further I need to display my error message above the check boxes as Larry did to textarea. I tried like this in my form function... but I can't get my error message... can anybody tell me where I have gone wrong???? this code is my form function. } elseif ($type == 'checkbox') { if ( $name == 'option[]' ) { // Display the error first: if (array_key_exists($name, $errors)) echo ' <span class="error">' . $errors[$name] . '</span>'; // Start creating the textarea: echo '<input type="' . $type . '" name="' . $name . '" value="1" class="checkbox" /> Individual<br />'; echo '<input type="' . $type . '" name="' . $name . '" value="2" class="checkbox" /> Small Groups <small>( Below 10 )</small><br />'; echo '<input type="' . $type . '" name="' . $name . '" value="3" class="checkbox" /> Medium Groups <small>( Between 10 to 20 )</small><br />'; echo '<input type="' . $type . '" name="' . $name . '" value="4" class="checkbox" /> Big Groups <small>( Over 20 )</small><br />'; echo '<input type="' . $type . '" name="' . $name . '" value="5" class="checkbox" /> Online Tuition<br />'; } if ( $name == 'medium[]' ) { // Display the error first: if (array_key_exists($name, $errors)) echo ' <span class="error">' . $errors[$name] . '</span>'; // Start creating the textarea: echo '<input type="' . $type . '" name="' . $name . '" value="1" class="checkbox" /> Hindi<br />'; echo '<input type="' . $type . '" name="' . $name . '" value="2" class="checkbox" /> English<br />'; echo '<input type="' . $type . '" name="' . $name . '" value="3" class="checkbox" /> Tamil<br />'; } }// End of primary IF-ELSE. These are my register.php page // Check for Institute Options: if(empty( $_POST['option'])) { $reg_errors['option'] = 'Please select at least one tuition option'; } else { $option = $_POST['option']; } // Check for Institute medium: if(empty( $_POST['medium'])) { $reg_errors['medium'] = 'Please select at least one tuition medium'; } else { $medium = $_POST['medium']; } This is My HTML part in register page <div> <label for="option">Tutoring Option <img src="../images/required_star.png" alt="required" /> : </label> <div class="checkbox1"> <?php create_form_input('option[]', 'checkbox', $reg_errors);?> </div> </div> <div> <label for="option">Tutoring Medium <img src="../images/required_star.png" alt="required" /> : </label> <div class="checkbox1"> <?php create_form_input('medium[]', 'checkbox', $reg_errors);?> </div> </div> any helps are greatly appreciated... thank you..