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I am trying to do the pursue question that says modify edit_user.php so that the form elements' values come from $_POST, if set and the database if not. Here is what I came up with but I get an error message saying Parse error: syntax error, unexpected 'if' (T_IF), expecting ',' or ';' in D:\xampp\htdocs\2book\ch9\edit_user.php on line 78 Here is my code. $q = "SELECT first_name, last_name, email, pass FROM users WHERE user_id=$id"; $r = @mysqli_query ($dbc, $q); if (mysqli_num_rows($r) == 1){ $row = mysqli_fetch_array($r, MYSQLI_NUM); echo '<form action="edit_user.php" method="post"> <p>First Name: <input type="text" name="first_name" size="15" maxlength="15" value="' if (isset($_POST['first_name'])){ echo $_POST['first_name']; } else { echo $row[0]; } '"/></p> <p>Last Name: <input type="text" name="last_name" size="15" maxlength="30" value="' . $row[1] . '" /></p> <p>Email Address: <input type="text" name="email" size="20" maxlength="60" value="' . $row[2] . '" /></p> <p>Password: <input type="password" name="pass1" size="10" maxlength="40" value="' . $row[3] . '" /></p> <p>Confirm Password: <input type="password" name="pass2" size="10" maxlength="40" value="' . $row[3] . '" /></p> <p><input type="submit" name="submit" value="Submit" /></p> <input type="hidden" name="id" value="' . $id . '" /></form>'; } else { echo '<p class="error">This page has been accessed in error.</p>'; }