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  1. Hello Larry and Hello Community, I bought book php and mysql for dynamic web sites in english from USA since i didn't see it in my native language. I gave a look all book for make general feeling and then i will read better and careful example and teching suggestions. Book is very very good in my opinion. My question is about what is best techinque to store html inside mysql database. I'm studying a bit how work CKeditor, but i think many html editor work more or less in same way, and it use a textarea to collect the html, so what you really need to do after a submit or similar processes is simply get the value of texarea and use php to store html in database. I'm asking how handle security, quote and double symbols or other problems. If i have understand i can use directly mysql_real_escape when i get textarea, simply before send html inside mysql or i can use prepared statement and in this case i think i can't use mysql_real_escape so i need pheraps to use htmlentities. I'm a little confuse about conflict you could have use both htmlentities, prepared statement, mysql_real_escape, etc.. I'm not exactly sure how i is best way general speaking in term of 100% secutiry and in term or not ruin html inside mysql and also i'm not sure what is procedure to make the contrary, i mean get html from mysql and serve i in page. Thanks very much. Andrea
  2. I don't know if anybody can put me through how to install composer on live server as I find little or no success at all on the net about how to do it
  3. Script 10#4 works for pagination, in my case 6 pages. Script 10#5 sort on First Name and Last Name work on the initial page display after selected column heading but not for selecting pages after the sort selection. My url shows view_users_3.php as I save each iteration of the scripts to review. Viewing my page then selecting sort by last name shows: url = view_users_3.php?sort=ln The first page of results displays correctly by last name. selecting the page 2: url = view_users_3.php?s=10&p=6&sortln The second page of results is showing user_id's 10 to 19 so has not sorted by last_name. The same situation occurs when I use First Name and Date Registered. I rechecked the code and noted lines 68-70 with the href tags (also from forum Sep 2013) not highlighted but cannot find any other difference with my code. My code: <?php # Chapter 10: Script 10.5: view_users_3.php //This script retrievs all the records from the users table. //This 10.5 version allows results to be sorted in different ways. $page_title = 'View the Current Users'; include ('../includes/header.html'); echo '<h1>Registered Users</h1>'; // Page header require_once ('../includes/mysqli_connect.php'); // Connect to the db. // Number of records to show per page. $display = 10; // Determine how many pages there are ... if (isset($_GET['p']) && is_numeric ($_GET['p'])) { // Already been determined. $pages = $_GET['p']; } else { // Need to determine. // Count the number of records. $q = "SELECT COUNT(user_id) FROM users"; $r = @mysqli_query ($dbc, $q); $row = @mysqli_fetch_array ($r, MYSQLI_NUM); $records = $row[0]; // Calcualte the number of pages... if ($records > $display) { // More than 1 page. $pages = ceil ($records/$display); } else { $pages = 1; } } // End of p IF. // Determine where in the database to start returning results... if (isset($_GET['s']) && is_numeric ($_GET['s'])) { $start = $_GET['s']; } else { $start = 0; } // Determine the sort... // Default is by registration date. $sort = (isset($_GET['sort'])) ? $_GET['sort'] : 'rd'; // Determine the sorting order. switch ($sort) { case 'ln': $order_by = 'last_name ASC'; break; case 'fn': $order_by = 'first_name ASC'; break; case 'rd': $order_by = 'registration_date ASC'; break; default: $order_by = 'registration_date ASC'; $sort = 'rd'; break; } // Define the query: $q = "SELECT last_name, first_name, DATE_FORMAT(registration_date, '%M %d, %Y') AS dr, user_id FROM users ORDER BY $order_by LIMIT $start, $display"; $r = @mysqli_query ($dbc, $q); // run the query. // Table header. echo '<table align="center" cellspacing="3" cellpadding="3" width="75%"> <tr> <td align="left"><b>Edit</b></td> <td align="left"><b>Delete</b></td> <td align="left"><b><a href="view_users_3.php?sort=ln">Last Name</a></b></td> <td align="left"><b><a href="view_users_3.php?sort=fn">First Name</a></b></td> <td align="left"><b><a href="view_users_3.php?sort=rd">Date Registered</a></b></td> </tr> '; // Fetch and print all the records. $bg = '#eeeeee'; // Set the initial background color. while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) { $bg = ($bg=='#eeeeee' ? '#ffffff' : '#eeeeee'); // Switch the background color. echo '<tr bgcolor="' . $bg . '"> <td align="left"><a href="edit_user.php?id=' . $row['user_id'] . '">Edit</a></td> <td align="left"><a href="delete_user.php?id=' . $row['user_id'] . '">Delete</a></td> <td align="left">' . $row['last_name'] . '</td> <td align="left">' . $row['first_name'] . '</td> <td align="left">' . $row['dr'] . '</td> </tr> '; } // End of WHILE loop. echo '</table>'; //Close the table. mysqli_free_result ($r); // Free up the resources. mysqli_close($dbc); // Close the database connection. // Make the links to other pages, if necessary. if ($pages > 1) { echo '<br /><p>'; // Add some spacing and start a paragraph. $current_page = ($start/$display) + 1; // Determine what page the script is on. // If it's not the first page, make a previous link: if ($current_page != 1) { echo '<a href="view_users_3.php?s=' . ($start - $display) . '&p=' . $pages . '&sort=' . $sort . '">Previous</a> '; } // Make all the numbered pages. for ($i = 1; $i <= $pages; $i++) { if ($i != $current_page) { echo '<a href="view_users_3.php?s=' . (($display * ($i - 1))) . '&p=' . $pages . '&sort' . $sort . '">' . $i . '</a> '; } else { echo $i . ' '; } } // End of FOR loop. // If it's not the last page, make a Next button. if ($current_page != $pages) { echo '<a href="view_users_3.php?s=' . ($start + $display) . '&p=' . $pages . '&sort' . $sort . '">Next</a>'; } echo '</p>'; // Close the paragraph. } // End of links section. include ('../includes/footer.html'); ?>
  4. i have some css tags in the header for my stylesheet and bootstrap and i tried to include the header.html as learnt from the book but it failed to load up instead it load up plain html. -My index.php: <?php require ('includes/config.inc.php'); $page_title = 'Homepage'; include ('includes/header.html'); ?> <?php include ('includes/footer.html'); ?> -My header.html: <!DOCTYPE html> <html> <head> <meta charset="utf-8" /> <meta http-equiv="X-UA-Compatible" content="IE=edge" /> <meta name="viewport" content="width=device-width, initial-scale=1" /> <title><?php echo $page_title; ?></title> <link href="../css/bootstrap.min.css" rel="stylesheet"> <link href="nav.css" rel="stylesheet"> <script src="http://cdn.ckeditor.com/4.6.1/standard/ckeditor.js"></script> </head> <body> <nav class="navbar navbar-default"> <div class="container"> <div class="navbar-header"> <button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#navbar" aria-expanded="false" aria-controls="navbar"> <span class="sr-only">Toggle navigation</span> <span class="icon-bar"></span> <span class="icon-bar"></span> <span class="icon-bar"></span> </button> <a class="navbar-brand" href="#">WEBNAME</a> </div> <div id="navbar" class="collapse navbar-collapse"> <ul class="nav navbar-nav"> <li class="active"><a href="../index.php">Home</a></li> <li><a href="../pages.html">Recent</a></li> <li><a href="../posts.html">Posts</a></li> <li><a href="../users.html">Users</a></li> </ul> <ul class="nav navbar-nav navbar-right"> <li><a href="#">Welcome</a></li> <li><a href="login.php">Logout</a></li> </ul> </div><!--/.nav-collapse --> </div> </nav> PLEASE HELP
  5. Good day! First off, great book sofar! I am only on chapter 2 and I love it. (I don't have excel tho so unsure if the database parts will work) Anywho, I am creating different handle_forms to see if I can have it give different responses as I go along. However, it constantly reverts back to handle_form.php even when I go into the html document and change <form action="handle_form.php" method="post"> to <form action="handle_form1.php" method="post"> Am I missing something on how to do that to test different forms?
  6. Hello, Hope you are doing great. I belong to a web development community and recently got hired in a logo design company to manage their site development issues. Basically, the website is designed quite well without any front-end issues but it has some backend issues that needs to be fixed. As they have given me a new task to add up a CMS into the backend of their website. I have already worked on Word press so I know how to configure it but as they want it on Drupal platform, I don’t know much about it. Although I have used Drupal and other CMS sites too but never got a chance to configure it in my previous experiences. So, here is what the error looks like: (see image below) An AJAX HTTP error occurred. HTTP Result Code: 200 Debugging information follows. Path: /drupal/core/install.? rewrite=ok&langcode=en&profile=standard &continue=1&id=1&op=do_nojs&op=do StatusText: OK ResponseText: Fatal error: Maximum execution time of 30 seconds exceeded in C:\xampp\htdocs\drupal\core\lib\Drupal\Core\ Database\Statement.php on line 59 Now, I would really appreciate if you could let me know how to get this issue fixed. Because the website is already built on using PHP so I am sure it won’t be that difficult to handle this error. Looking forward towards your valuable comments.
  7. Hi Larry I thought that I'd post this as it might help other php-ers. I have a website which has many images. To facilitate the download of images, I save a reduced image under a directory name e.g. images/activities/P3451098.jpg for thumbnails and slideshows as well as the full size in e.g. images/raw/P3451098.jpg. Then I can offer an enlarged image using <a href = ***><img src...... target = "_blank"> etc. The problem is that as I send the images up using FTP (Filezilla) I can't be sure if all of the reduced images have the corresponding full sized images thanks to advanced dementia. Therefore, I have written a short routine to compare the two directories.... COMMENTS: 1) I was confused at first as to why it didn't work properly until I discovered that glob() is case sensitive, so that it wasn't finding .JPGs so had to run it twice (there is a variety of both depending on which camera they came from). 2) The search routine is not very elegant as it runs through all of the raw files even though it may have found a match in the first file. 3) I know that I could use glob(images/raw/*.*) instead of glob(images/raw/*.*) and in this case it wouldn't make any difference as all files in these directories are .jpgs - it just seems more precise to use *.jpg. I would appreciate any comments from anybody..... <?php //Declare variable $found to avoid undefined variable errors $found = "No"; //Call header which handles security and error messages include ('adminheader.php'); //Create an array $images which lists all of the relevant image directories on the server.. $images = array('4X4', 'activities', 'almonds', 'alojamiento', 'altiplano', 'archery', 'area', 'artifacts', 'baza', 'castillejar', 'castril', 'caving', 'fiestas', 'flowers', 'history', 'huescar', 'kayaking', 'index', 'markets', 'mountaineering', 'mountains', 'museums', 'photography', 'puebla', 'rafting', 'village', 'wildlife', 'activities/activities', 'activities/caving', 'activities/kayaking', 'activities/mountaineering', 'activities/outdoors', 'activities/rafting'); //Create array $raw which will be a listing of all of the large image files on the server $raw = glob('images/raw/*.jpg'); $raw2 = glob('images/raw/*.JPG'); //Work through the $images array so as to compare whether there is a large matching file in the 'raw' directory... foreach($images as $key => $category) { //Start with a header to ID each category.... echo 'CATEGORY:... ' . $category . '<br /><br />'; //Now create a variable ($getlisting) to be able to call only the category that we are interested in... $getlisting = 'images/' . $category . '/*.jpg'; //create an array of the files in this category.. $listing = glob($getlisting); //Run through the $raw array to see if it contains a file that matches the file in the category... foreach($listing as $key => $value) { //Create variable to use in str_replace.. $directory = 'images/' . $category . '/'; // Remove the unwanted directory details.... $value = str_replace($directory, "", $value); //Reduce any JPGs to jpgs... $value = strtolower($value); //Run through the $raw array to find a match.. foreach($raw as $key => $rawvalue) { //Get rid of directory details from $rawvalue... $rawvalue = str_replace("images/raw/", "", $rawvalue); //Bring any .JPGs to .jpgs.... $rawvalue = strtolower($rawvalue); //Do comparison. If raw image matches reduced image then do nothing.. if ($value == $rawvalue) { //If the small and large files match then switch variable $found to 'on'.... $found = "Found"; } } //Run through the $raw array to find a match.. foreach($raw2 as $key => $rawvalue) { //Get rid of directory details from $rawvalue... $rawvalue = str_replace("images/raw/", "", $rawvalue); //Bring any .JPGs to .jpgs.... $rawvalue = strtolower($rawvalue); //Do comparison. If raw image matches reduced image then do nothing.. if ($value == $rawvalue) { //If the small and large files match then switch variable $found to 'on'.... $found = "Found"; } } //If small and large files don't match, then print out the filename .. if ($found != "Found") { echo $value . "<br /><br />"; } //reset $found to "Not found".. $found = "No"; } //Close individual Category foreach echo "<br /><br />"; } //Close all category foreach echo "ALL DONE!"; include ('footer.php'); ?>
  8. This is related to another question I asked that I haven't managed to resolve, so I'm trying something else! I have an associative array fetched from mysql, and I need to sum values based on the value in a different column. I have created an associative array, and printed to screen and it looks okay. It returns what I need, and looks like [1] => 779700.00 ) Array ( [4] => 868.00 ) Array ( [2] => 102000.00 ) Array ( [2] => 775808.00 My problem is that I need to be able to sum the results for each individual key value pair (so eg '2' would sum to 877808.00) - there are only eight key values, and I need a variable to hold each one. I have read lots of similar questions and have tried the solutions, but have just got myself hopelessly confused. I assume I need a foreach loop, please could somebody point me in the right direction for what I need to do? I'm not sure if I'm barking up the wrong tree or not. Thanks. while($row_outputs=mysqli_fetch_array($run_projects)) { $Id = $row_outputs['id']; $impact = $row_outputs['impact']; $cost = $row_outputs['total_cost']; $summing_array = array($impact=>$cost);
  9. I'm having a bit of a problem which I think I might know the solution, but I'm really struggling to know the correct syntax. If somebody could point me in the right direction I'd be very grateful. I've created an application where users can create projects, and within the projects there are 'outputs' and 'inputs'. All of which is stored in separate MySql tables. It works fine. I have now been asked to create an addition layer, a 'programme' layer, which sits above projects (ie there can be multiple projects within one programme). I think I have got my table normalisation correct, I created 2 tables, 'programmes' which stores programme id and name etc, and 'programmes_projects' which stores only the programme id and the project id. That seems to work ok. What I'm having trouble with, is displaying the results correctly. I need to retrieve information from 4 (actually 5) related MySql tables. Phew. I think I need to create an associative array and a foreach loop, but because of the number of tables and the relationships, I'm getting very confused. I'm not sure if I should be focussing on the sql statements, the php, or what. I tried using while loops, because that's what I know, but wasn't surprised that it didn't work. progId = $_GET['prog']; //get the individual projects from the linking db table $get_projects = "SELECT * FROM programmes_projects WHERE prog_id=$progId"; $run_projects = mysqli_query($conn, $get_projects); $i = 0; while($row_projects=mysqli_fetch_array($run_projects)){ $prog_proj_id = $row_projects['prog_proj_id']; $prog_id = $row_projects['prog_id']; $projectId = $row_projects['proj_id']; $i++; //attempting to collect project details from the outputs table $get_proj_details = "SELECT * FROM projects WHERE project_id=$projectId"; $fetch_projects = mysqli_query($conn, $get_proj_details); $i = 0; while($row_details=mysqli_fetch_array($fetch_projects)){ $proj_name = $row_details['project_name']; $proj_whatever = $row_details['date']; $i++; // project outputs $fetch_outputs = "SELECT * FROM projects_outputs WHERE project_id=$projectId"; $get_outputs = mysqli_query($conn, $fetch_outputs); $i = 0; while($row_outputs=mysqli_fetch_array($get_outputs)){ $out_id = $row_outputs['output_id']; $output_desc = $row_outputs['output_desc']; $i++; }}}?> Please could someone help?? Even if it's just a nudge in the right direction. Thank you very much.
  10. Hi Larry my name is sam can i first start by saying i absolutely love your books. i am currently working on a project where i have built the php side of things and now working on enhancing using javascript. i am adapting your script from your Modern javascript develop and design book on chapter 15, (view.js). But the problem i have is my php script loops through the database to show results and i am trying to pass the id of the data, like you do in your view.php script to the view.js script with, <script> var itemId = ' . $itemid .'; </script> BUT i have a while loop on the php script and the script tags are in the while loop like this, $query = "SELECT `item_id` FROM items"; $results = mysqli_query ($dbc, $query); while (list ($item_id ) = mysqli_fetch_array($results, MYSQLI_NUM)) { // Start the while Loop here ... echo '<form action="" method="post" id="bidForm" class="bidForm"> <input class="button" type="submit" value="Like" title="Like"> <input type="hidden" name="item_id" id="item_id" class="video" value="' . $item_id . '"> </form>'; ?> <script> var itemId = "<?php echo $item_id; ?>"; </script> } // End of while Loop here .. then link to external js script <script src="js/ajaxBid.js"></script> Just so you know this is not exact just example above but it does the exact same thing. So the problem is where it Loops the var itemId gets more then one value so you don't get the value of the button clicked sent to the ajax script. How can i get the id of the button clicked in my js script while still in the while loop???? sorry if this is really confusing i will answer any questions you might have. if you or anyone could explain in the simplest possible way where I'm going wrong as not brilliant at javascript yet, that would be amazing been stuck for ages on this. many thanks, Sam
  11. Hi I'm trying to find out 2 things, 1) how to pass a button value that comes from mysqli while loop to javascript then on to Ajax script. 2) how to pass a php array on to javascript and then onto the Ajax script. I will be really grateful if anyone could help. many thanks sam
  12. Here's a general question... I suspect most of us have done it at some time - I certainly have - uploading a program by mistake to a server, that has an infinite loop in it (usually 'while(){....}') which means that the program whizzes round a million times sending hundreds of error messages to your e-mail address. QUESTION: Eventually the server will kill the program automatically, but is there any way (in php or otherwise server-side) to kill it? I suppose one could add a line in the loop such as $x+; if (x$>'1000'){die()} to save this embarrassment! "To err is human, but it takes a computer to REALLY $&** things up!!"
  13. There is something about php that I have trouble understand coming from using javascript like angular. How does routing in php work exactly? Like how does a php site know about going to a link (/browse/coffee/Dark+Roast/2) or a shop/product link. How does the htacess file works with the site. Currently, when going to a link the /shop/coffee, it responds by not found. I tried to look it up but I don't understand it per say as it different from the way I normally do it in javascript. <body id="page1"> <!-- header --> <div id="header"> <div class="container"> <div class="wrapper"> <ul class="top-links"> <li><a href="/index.php" class="first"><img alt="" src="/images/icon-home.gif" /></a></li> <li><a href="/cart.php"><img alt="" src="/images/icon-cart.gif" /></a></li> <li><a href="/contact.php"><img alt="" src="/images/icon-mail.gif" /></a></li> <li><a href="/sitemap.php"><img alt="" src="/images/icon-map.gif" /></a></li> </ul> <div class="logo"> <h1><a href="/index.php">Coffee</a><span>Wouldn't you love a cup right now?</span></h1> </div> </div> <ul class="nav"> <!-- MENU --> <li><a href="/shop/coffee/">Coffee</a></li> <li><a href="/shop/goodies/">Goodies</a></li> <li><a href="/shop/sales/">Sales</a></li> <li><a href="/wishlist.php">Wish List</a></li> <li><a href="/cart.php">Cart</a></li> <!-- END MENU --> </ul> </div> </div> <!-- content --> <div id="content"> <div class="container"> <div class="inside">
  14. I've just started this book and am really confused with an expression. Can somebody please explain the mechanism behind the expression, given below, used in Script 1.1 - sort.php return ($x < $y) // Creating an array $a = [1, 5]; // creating comparison function using the above expression function comp1($x, $y) { return ($x < $y); } // using uasort() uasort($a, 'comp1'); // output the result echo '<pre>' . print_r($a, 1) . '</pre>'; // creating the same function as above but interchanging the arguments position function comp2($y, $x) { return ($x < $y); } // using uasort() uasort($a, 'comp2'); // output the result echo '<pre>' . print_r($a, 1) . '</pre>'; This outputs Array ( [1] => 5 [0] => 1 ) Array ( [0] => 1 [1] => 5 ) Observation: reversing the position of arguments in function definition reverses the sort output. Can somebody please explain the 'mechanism' about using the expression return ($x < $y) - How and which values are returned.
  15. I am looking to recreate the following function from PDO to MySQLi but having some problems, I've been over the PHP website to read the functions. I'm trying to modularize my code in like the MVC pattern. public function bind($param, $value, $type=''){ if(is_null($type)){ switch(true){ case is_int($value): //Thinking something like, for integer etc $type = mysqli_stmt::bind_param(i); $type = PDO::PARAM_INT; break; case is_bool($value): $type = PDO::PARAM_BOOL; break; default: $type = PDO::PARAM_STR; } } $this->stmt->bindvalue($param,$value,$type); } Is it as simple as just replacing PDO version line to : $type = mysqli_stmt::bind(i); or just putting $type = i; Then in my class I am trying to call the bind function: $database ->bind($stmt,$ype,$variables); $database->execute(); Any help would be much appreciated Regards My Setup Chrome Windows XP Wamp SublimeText
  16. OS: Windows 7 php version: 5.5.8 (running on EasyPHP Dev Server 14.1 VC11) Browser: Firefox 40.0.2 (same results in Chrome and IE) I am having problems with the show_image script in chapter 11. When I select an image from the list it opens a popup window of the appropriate size but with no image. In firefox I get the error message: 'The image "http://127.0.0.1/scripts/site/show_image.php?image=Picture.png"cannot be displayed because it contains errors.' When I use the Web Developer menu to View Response Headers all is as expected except that it lists Content-Length: 0. I commented out the header calls and replaced them with echos: echo "Content-Type: {$info['mime']}</br>"; echo "Content-Disposition: inline; filename=\"$name\"</br>"; echo "Content-Length: $fs"; Which return the values you would expect: Content-Type: image/png Content-Disposition: inline; filename="Picture.png" Content-Length: 35880 I changed the Content-Disposition to attachment. The files download as normal with the appropriate file names but have a size of 0. When I try to open them I get the error message: "Windows Photo Viewer can't display this picture because the file is empty." I double checked the files in the upload folder and they are all normal .png files. My code is below. Any advice you can offer would be very gratefully received. Adam show_image.php <?php $name = FALSE; if (isset($_GET['image'])) { //echo 'Image set </br>'; $ext = strtolower(substr($_GET['image'], -4)); if (($ext == '.jpg') OR ($ext == 'jpeg') OR ($ext == '.png')) { //echo 'Correct ext </br>'; $image = "../uploads/{$_GET['image']}"; if (file_exists($image) && (is_file($image))) { //echo 'File exists </br>'; $name = $_GET['image']; } } } if (!$name) { //echo 'Unavailable'; $image = 'images/unavailable.png'; $name = 'unavailable.png'; } $info = getimagesize($image); $fs = filesize($image); header ("Content-Type: {$info['mime']}\n"); header ("Content-Disposition: inline; filename=\"$name\"\n"); header ("Content-Length: $fs"); //echo "Content-Type: {$info['mime']}</br>"; //echo "Content-Disposition: inline; filename=\"$name\"</br>"; //echo "Content-Length: $fs"; images.php <!DOCTYPE html PUBLIC "-//W3C// DTD XHTML 1.0 Transitional//EN" "http:/www.w3.org/TR/xhtml/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"xml:lang="en" lang="en" <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Images</title> <script type="text/javascript" charset="utf-8" src="js/function.js"></script> </head> <body> <p>Click on an image to view it in a separate window.</p> <ul> <?php # Script 11.4 - images.php $dir = '../uploads'; $files = scandir($dir); foreach ($files as $image) { if (substr($image, 0 , 1) != '.') { $image_size = getimagesize ("$dir/$image"); $image_name = urlencode($image); echo "<li><a href=\"javascript:create_window('$image_name',$image_size[0],$image_size[1])\">$image</a></li>\n"; } } ?> </ul> </body> </html> function.js // Script 11.3 - function.js function create_window (image, width, height) { width = width + 10; height = height + 10; if (window.popup && !window.popup.closed) { window.popup.resizeTo(width, height); } var specs = "location=no, scrollbars=no, menubars=no, toolbars=no, resizeable=yes, left=0, top=0, width=" + width + ", height=" + height; var url = "show_image.php?image=" + image; popup = window.open(url, "ImageWindow", specs); popup.focus(); }
  17. Hi Larry, Hope your having a good day today as you read this message. I just want to get some advice from you personally. My problem is I really would like to be a good programmer like you larry. But I think that cannot be accomplished easily. I just wanna know what are your strategies when your just starting out as a developer. How many hours you read a book in PHP js or mysql? and how do you know if its time to move in a diff topic like ex. procedural to object oriented. Coz I think I'm having a bad habit of reading a book like, after I read a single book i'll read another book right away then I tend to forget what i've learned in the previous book. So what i usually do is I will try go back to the previous book just to refresh what i've learned. And i'm not sure if I'm doin the correct way to learn. I'm really amazed on you larry bec you know not only 1 programming language. So I just wanna know your strategies on learning. I'm very sorry for my english by the way, and I know your a super busy person. I will really appreciate your reply Larry. And I hope you understand my point. Thank you so much in advance. Regards, Jan
  18. I'm having an issue with mysql_real_escape_string. This is used to display a custom post type (food menu items) for the WooThemes Diner theme (for WordPress). Food menu items no longer display on the Diner menu page because they are being called with mysql_real_escape_string. What is the proper way to call these items? Theme: Diner by WooThemes version 1.9.8 (now retired from active support) Affected file: admin-interface.php Lines: 111 & 118 /*-----------------------------------------------------------------------------------*/ /* WooThemes Admin Interface - woothemes_add_admin */ /*-----------------------------------------------------------------------------------*/ if ( ! function_exists( 'woothemes_add_admin' ) ) { function woothemes_add_admin() { global $query_string; global $current_user; $current_user_id = $current_user->user_login; $super_user = get_option( 'framework_woo_super_user' ); $themename = get_option( 'woo_themename' ); $shortname = get_option( 'woo_shortname' ); // Reset the settings, sanitizing the various requests made. // Use a SWITCH to determine which settings to update. /* Make sure we're making a request. ------------------------------------------------------------*/ if ( isset( $_REQUEST['page'] ) ) { // Sanitize page being requested. $_page = ''; $_page = mysql_real_escape_string( strtolower( trim( strip_tags( $_REQUEST['page'] ) ) ) ); // Sanitize action being requested. $_action = ''; if ( isset( $_REQUEST['woo_save'] ) ) { $_action = mysql_real_escape_string( strtolower( trim( strip_tags( $_REQUEST['woo_save'] ) ) ) ); } // End IF Statement // If the action is "reset", run the SWITCH. /* Perform settings reset. ------------------------------------------------------------*/
  19. So...I'm just getting really frustrated now. I've been reading through several of these chapters several times. My school always tends to not choose books well. On to the issue though. In several sections I've noted it stating "Connect to MySQL and select the forum database." This is where the issue lies. I have MySQL and PHP installed in both operating systems of my laptop (Linux and Windows) and in neither does the referenced database exist. The book does not even state WHERE or HOW to have this included. How is a person supposed to follow the examples if some crucial components were left out? It's like giving directions by saying "Just follow me" while in a car to a person on a bicycle. Saying follow me would be completely worthless. If someone can at least point me in the right direction to actually have these referenced databases...or to a quality book. Either way.
  20. Ok I haven't followed the code 100% by which I mean only that I didn't include the XHTML parts in the <!DOCTYPE> tag. I understand that this is not vital however. Other than that I think I have followed it correctly. I keep getting http error 500 in the browser however when I try to load it. However other php scripts seem to load fine so I don't think it's a problem with MAMP. Here is my code: <!DOCTYPE html> <html> <head> <meta charset="utf-8" http-equiv="Content-Type" content="text/html"> <title>Calendar</title> </head> <body> <form action="calendar.php" method="post"> <?php # Script 2.6 - Calendar.php //This script makes 3 pulldown menus //For an html form: months, days, years. //make months array $months = array (1 => 'January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'); //make the days and years array $days = range (1, 31); $years = range (2011, 2021); //make the months pull down menu: echo '<select name="month">'; for each ($months as $key => $value) { echo "<option value=\"$key\">$value</option>\n"; } echo '</select>'; //make the days pull-down menu: echo '<select name="day">'; foreach ($days as $value) { echo "<option value=\"$value\">$value</option>\n"; } echo '</select>'; //make the years pull-down menu: echo '<select name="year">'; foreach ($year as $value) { echo "<option value=\"$value\"> $value</option>\n"; } echo "</select>"; ?> </form> </body> </html> It's probably something incredibly obvious and embarrassing but any help would be gratefully received. I'm going to skip ahead and read the section of bug fixing while I wait for a response so maybe I will find the answer there. Thanks in advance.
  21. In chapter 4 if I click on the Account tab once logged in, no links appear that allow me to change my password or logout, the account link is a dead link?. It is supposed to give me the option to logout and other links too. I am using the files from the download on this site. I finally found the problem, there is no bootstrap.min.js file in the downloads for this book. That is why the dropdown menu wasn't working. I went to the bootstrap site and downloaded and now it works fine. This really should be in the download files...
  22. In the source code and as well as the book you write if (isset($_SESSION['user_id']) && !isset($_SESSION['user_not_expired'])) { echo '<div class="alert"><h4>Expired Account</h4>Thank you for your interest in this content. Unfortunately your account has expired. Please <a href="renew.php">renew your account</a> in order to access site content.</div>'; } elseif (!isset($_SESSION['user_id'])) { echo '<div class="alert">Thank you for your interest in this content. You must be logged in as a registered user to view site content.</div>'; } and it displays the error that the member needs to renew, However I set the date to expire a month out on both my admin and member logins. when I take out the "!" from the second parameter it fixes the problem and the error message goes away. Was the "!" a mistake or am I not doing something correctly? I have been running off of the full scripts download and only tweaking things to sync up with my database. Also after I removed the "!" when I click on a category after it displays no error and I go to a page.php and click back to a category, or click on a different/same category I get the error to renew. Insights would be greatly appreciated.
  23. On page 124 it says you can use sql commands from your website to populate the database. But the sql commands I got from the download don't have any sample content, all that is in the sql commands is the commands to add the tables to the database. No content. Where can I get the file with the data to populate the tables. Please indicate the url where I can download that. I am trying to populate the pages myself but I keep getting the error which says Please select a category! I added 2 numeric categories to the categories table, but the form still won't accept it. There seems to be a problem with the code of the select menu. I could really use some help with this part of the book. Some help would be appreciated.
  24. hello, I have starting reading the PHP and MySQL 4th edition book by LarryUllman. So far I have completed first four chapters and now starting 5th chapter. But, with time as I read further, I also want to develop good skills i.e be good in what I am learning. So can anyone suggest me some startup projects? or scripts etc I can try to code, so I can be more good in programming. Regards,
  25. Hi Larry. I have a problem with this script. The table show me files list correctly with name and size. When I click on link popup appear perfectly resized but no image was loaded. Popup show a copy of show_image.php resized. No errors on firebug. If I change: var url = "show_image.php?image="+image; with var url = "upload/"+image; everythings works fine. any suggestions? Sorry for my english. Greetings Cecchi Luca
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