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Found 183 results

  1. My question is why in the following mysql statement does the $id at the end, not have to be in single quotes, whereas other variables in this statement are in quotes. $u = "UPDATE customers SET first_name='$fn', last_name='$ln', email='$em', address='$add', zipcode='$zip', city='$city', state='$state', country='$coun' WHERE customer_id = $id";
  2. I am using the structure of Script 3.5 (Calculator.php) to tackle the issue of recording attendance for persons listed in a MySQL database. I am using this structure because I am attempting to create a web page that will handle a form and then display it again. Larry mentions this function on page 86. I plan to use input type="checkbox" name="checkbox[]" value="full_name". The value part is where I am having trouble. I want to select a person's name from a table in the database so that the name will appear on the form on the same line with the checkbox. The page is in two parts, the first part being for php code, and the second part being for the html form. To place on the form a checkbox I need to list a person's name with that input. I can query the database in the php section and fetch from the array of results each person's name. Can anyone suggest where in the code I can fetch the names and then use them in the input for checkboxes? I hope this makes sense. I want to record attendance for all persons in a table who are present at a meeting. I want to list the names of all persons in the table along with a checkbox that can be checked to indicate they were present. I will appreciate any guidance that can be shared to help me in designing a plan to accomplish this. Thank you. Wes (wesmith4@gmail.com)
  3. I have an HTML table generated by PHP querying from MySQL table. <table> <tr> <th>Sl</th> <th>ID</th> <th>Article Name</th> <th>Publish Status</th> </tr> <?php $i = 1; foreach ($obj->showAllFromTable('pattern') as $pattern) { extract($pattern); ?> <tr> <td><?php echo $i++; ?></td> <td><?php echo $id; ?></td> <td><?php echo $pattern_name; ?></td> <td id="publish_<?php echo $id; ?>" class="status_pattern"> <?php echo $publish; ?> </td> </tr> <?php } ?> </table> I want to change the status of any article by clicking on the 'publish' cell of the corresponding article row. I am trying to use ajax method of jquery for this purpose as shown in the following: <script type="text/javascript"> $(document).ready(function(){ $('.status_pattern').click(function(){ var thisid = $(this).attr('id'); $.ajax({ url: "status_change_pattern.php", data: { id: thisid }, success: function (response) { alert(response); } }); }); }); </script> In the "success" block, instead of "alert", I want to create a functionality to change the text of the specific cell which I clicked. The "status_change_pattern.php" has just a text "Hey Hey". Can anyone help? Please. Thanks.
  4. Hello all, I am enjoying this book, and have had all success deploying the chapter 3 department select menu scripts on my local environment. When i try to implement the same when using a bootstrap style website, where the pages are outputted through the index.php file: https://mysite.com/index.php?page=dept_form&did=1 I run into problems. In your book on chapter 3 your dept.js file has the code pulling from (get, dept_results_ajax.php?did=' + encode...). Because of the bootstrap style site I am using will this be different? Also, does it matter if using https opposed to http? Any help would be great. Thanks
  5. I am almost finished the book, and I am not totally clear on how to use the $page_title variable that appears throughout the book, do we have to include the following code in the title tag of each php script in order to use $page_title. <?php echo $page_title; ?>. In most of the examples in this book the $page_title variable is used in the script without showing the code used in the title tag. Also since the $page_title variable appears below the title tag when I load the php script in my browser I get an error message saying that $page_title isn't a valid variable. Can someone explain to me how to properly use the $page_title variable when writing php scripts. Or is it just easier to write the title in the title tag without using this variable.
  6. I am attempting to develop a PHP script to record presence at an event for those persons in a mysql table Persons. I am attempting to use checkboxes to indicate who was present. Here is the script as currently written: <?php # Script require ('includes/mysqli_connect.php'); if(isset($_POST['checkbox'])) {$checkbox = $_POST['checkbox']; if(isset($_POST['activate'])?$activate = $_POST["activate"]:$deactivate = $_POST["deactivate"]); $id = "('" . implode( "','", $checkbox ) . "');" ; echo $id; $q="UPDATE Persons SET present = '".(isset($activate)?'Y':'N')."' WHERE id IN $id" ; $r = mysqli_query($dbc,$q) or die(mysqli_error()); } $q = "SELECT * FROM Persons"; $r = @mysqli_query ($dbc,$q); $count=mysqli_num_rows($r); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns=?http="//www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset="utf-8"" /> <title>Update multiple rows in mysql with checkbox</title> <script type="text/javascript"> <!-- function un_check(){ for (var i = 0; i < document.frmactive.elements.length; i++) { var e = document.frmactive.elements; if ((e.name != 'allbox') && (e.type == 'checkbox')) { e.checked = document.frmactive.allbox.checked; }}} //--> </script> </head> <body> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td><form name="frmactive" method="post" action="checkboxes.php"> <table width="400" border="0" cellpadding="3" cellspacing="1"> <tr> <td colspan="5"><input name="activate" type="submit" id="activate" value="Activate" /> <input name="deactivate" type="submit" id="deactivate" value="Deactivate" /></td> </tr> <tr> <td> </td> <td colspan="4"><strong>Update multiple rows in mysql with checkbox</strong> </td> </tr><tr> <td align="center"><input type="checkbox" name="allbox" title="Select or Deselect ALL" style="background-color:#ccc;"/></td> <td align="center"><strong>id</strong></td> <td align="center"><strong>first_name</strong></td> <td align="center"><strong>last_name</strong></td> <td align="center"><strong>present</strong></td> </tr> <?php while ($row = mysqli_fetch_array($r)) { ?> <tr> <td align="center"><input name="checkbox[]" type="checkbox" id="checkbox" id="checkbox[]" value="<? echo $rows['person_id']; ?>"></td> <td><? echo $row['person_id']; ?></td> <td><? echo $row['first_name']; ?></td> <td><? echo $row['last_name']; ?></td> <td><? echo $row['present']; ?></td> </tr> <?php } ?> <tr> <td colspan="5" align="center"> </td> </tr> </table> </form> </td> </tr> </table> </body> </html> The table Persons contains these columns: person_id, first_name,last_name,present. I inserted the echo line after the line defining $id which is copied below: $id = "('" . implode( "','", $checkbox ) . "');" ; echo $id; But $id only contains empty strings. Can anyone help me understand what I am doing wrong? Is $checkbox always ending up empty? Any direction will be appreciated. Wes Smith
  7. Can anyone provide me with a simple solution to the Pursue question in chapter 18, create a last_login field and make it so that a user can see how long it has been since they last logged in. thanks Graham
  8. Hi everyone. I've done everything I could think of to get Script 11.8 to work, but I keep getting the error message 'The username and password you entered do not match those on file'. The users.txt is where it should be (because it worked fine for register.php) and the script is almost exactly how it is in the book. I'm using the same user names and passwords as well. Is this happening because I'm on a Mac? Oh, I'm on PHP 5.3.6 and use XAMPP. <?php // Script 11.8 - login.php $file = '../users/users.txt'; if ($_SERVER['REQUEST_METHOD'] == 'POST') { // Handle the form. $loggedin = FALSE; // Not currently signed in. // Enable auto_detect_line settings: ini_set('auto_detect_line_endings', 1); // Open the file: $fp = fopen($file, 'rb'); // Loop through the file: while ( $line = fgetcsv($fp, 200, "\t") ) { // Check the file data against the submitted data: if ( ($line[0] == $_POST['username']) AND ($line[1] == md5(trim($_POST['password']))) ) { $loggedin = TRUE; // Correct username/password combination. // Stop looping through the file: break; } // End of IF. } // End of WHILE. fclose ($fp); // Close the file. // Print a message: if ($loggedin) { print '<p>You are now logged in.</p>'; } else { print '<p style="color: red;">The username and password you entered do not match those on file.</p>'; } } else { // Display the form. // Leave PHP and display the form: ?> <form action="login.php" method="post"> <p>Username: <input type="text" name="username" size="20" /></p> <p>Password: <input type="password" name="password" size="20" /></p> <input type="submit" name="submit" value="Login" /></form> <?php } // End of submission IF. ?> </body> </html>
  9. hey everybody, i have a request here,i'm a newbie in which called php and mysql.. i have finished the HTML of my website and now i want to implement a sidebar for Most Popular Posts.. i'masking if u can afford me with a tutorial from the scratch to build my sidebar? plz? thanks in advance
  10. 2 problems with my code, the filter_var doesn't seem to work at all for any of my variables, also the spam_scrubber function doesn't seem to clean \r, and \n, when put in my contact form, it cleans all the rest though just fine. <?php // resources.php function spam_scrubber($value){ $very_bad = array('to:', 'cc:', 'bcc:', 'content-type:', 'mime-version:', 'multipart-mixed:', 'content-transfer-encoding:'); foreach ($very_bad as $v){ if (stripos($value, $v) !== false) return ''; } $value = str_replace(array( "\r", "\n", "%0a", "%0d"), ' ', $value); return trim($value); }//end of spam_scrubber function $scrubbed = array_map('spam_scrubber', $_POST); $comments = strip_tags($scrubbed['comments']); $url = $scrubbed['url']; if (isset($url)){ filter_var($url, FILTER_VALIDATE_URL, FILTER_SANITIZE_URL); } else { echo NULL; } $url2 = $scrubbed['url2']; if (isset($url2)){ filter_var($url2, FILTER_VALIDATE_URL, FILTER_SANITIZE_URL); } else { echo NULL; } $linkpageurl = $scrubbed['linkpageurl']; if (isset($linkpageurl)){ filter_var($linkpageurl, FILTER_VALIDATE_URL, FILTER_SANITIZE_URL); } else { echo NULL; } $linkpageurl2 = $scrubbed['linkpageurl2']; if (isset($linkpageurl2)){ filter_var($linkpageurl2, FILTER_VALIDATE_URL, FILTER_SANITIZE_URL); } else { echo NULL; } $email = $scrubbed['email']; if (isset($email)){ filter_var($email, FILTER_VALIDATE_EMAIL, FILTER_SANITIZE_EMAIL); } else { echo NULL; } $pagerank = $scrubbed['pagerank']; if (isset($pagerank)){ filter_var($pagerank, FILTER_VALIDATE_INT, FILTER_SANITIZE_NUMBER_INT); } else { echo NULL; } if (!empty($email) && !empty($url) && !empty($linkpageurl) && !empty($comments) && !empty($pagerank)){ $body = "Email: {$email}\n\n Url: {$url}\n\n Url2: {$url2}\n\n Pagerank: {$pagerank}\n\n Linkpageurl: {$linkpageurl} \n\n Linkpageurl2: {$linkpageurl2}\n\n Comments: {$comments}"; $body = wordwrap($body, 70); $headers = "From: {$email}\r\n"; mail('email@example.com', 'Link Exchange Form Submission', $body, $headers); echo '<p><em>Thank you for contacting us.</em></p><div id="formecho"><h3>Form submission received, we will get back to you soon.</h3></div>'; $_POST = array(); } else { echo '<p style="font-weight: bold; color: #C00">Please fill out the form completely.</p>'; } ?> <div id="form"> <form action="linkexchangecontactform2.php" method="post"> <p><b>Email:</b> <input type="text" size="30" maxlength="50" name="email" value="<?php if(isset($scrubbed['submit']))echo $scrubbed['email']; ?>" /></p> <p><b>Url:</b> <input type="text" size="30" maxlength="50" name="url" value="<?php if(isset($scrubbed['url']))echo $scrubbed['url']; ?>" /></p> <p><b>2nd Url (leave empty if you have just 1 website):</b><br /> <input type="text" size="30" maxlength="50" name="url2" value="<?php if(isset($scrubbed['url2']))echo $scrubbed['url2']; ?>" /></p> <p><b>Pagerank:</b> <input type="text" size="5" maxlength="10" name="pagerank" value="<?php if(isset($scrubbed['pagerank']))echo $scrubbed['pagerank']; ?>" /></p> <p><b>Link page url:</b> <input type="text" size="30" maxlength="50" name="linkpageurl" value="<?php if(isset($scrubbed['linkpageurl']))echo $scrubbed['linkpageurl']; ?>" /></p> <p><b>2nd Link page url (leave empty if you have just 1 website):</b><br /> <input type="text" size="30" maxlength="50" name="linkpageurl2" value="<?php if(isset($scrubbed['linkpageurl2']))echo $scrubbed['linkpageurl2']; ?>" /></p> <p><b>Comments:</b><br> <textarea name="comments" rows="7" cols="40"><?php if (isset($scrubbed['comments'])) echo $scrubbed['comments']; ?></textarea></p> <p><input type="submit" name="submit" value="Submit" /></p> </form></div>
  11. I want to create a contact form that has an email field where the user can't enter any white space in the field, for example: test@ex ample.com I am using a spam scrubbing function taught to us in the book to clean user inputs. I am using my variable like so. $email = strip_tags($scrubbed['email']); how can I add something like this $email = preg_replace('/\s+/', '', $email); to the existing $email = strip_tags($scrubbed['email']); I tried $email = (preg_replace('/\s+/', '', $email)(strip_tags($scrubbed['email']))); and all sorts of variations to that. it doesn't work.
  12. Hi, I need some help with a php application. I want to write simple online scheduling/appointment application with PHP and MySQL. I am not sure how to begin. Basically these are what the application would allow: USERS : - to log in as member - choose the person (advisors) they want to make an appointment with - pick a date and time from available time slot For example, Feb 1, 2014, 8:00AM- 8:30AM - Submit the date to advisor (email confirmation) ADVISORS - to log in as an admin - set up their schedules (available date and time). - there are several advisors, each has seperate schedule. My questions are: - What tools/frameworks should be used to display Calendar and time? - What appropriate methods should I store advisors available date and time in MySQL? - If i use jquery UI to display calendar, how can I make it interact with the database? For example, GREEN is available time, RED is booked. Thanks for your input.
  13. I think my PEAR install is working and got the phpDocumentor installed but now get an error using it. "phpDocumentor.EMERGENCY: phpDocumentor detected that a requirement is missing in your system setup: The XSL writer was unable to find your XSLTProcessor: please check if you have installed the PHP XSL extension or XSLC ache extention." I have a windows 7 home premium 64 bit laptop with WAMP. My Wamp 2.2 settings are Apache: 2.2.22, PHP: 5.3.13, and MySQL: 5.5.24. I checked in my php.ini file from the wamp icon in my toolbar and it has the XSL extension on. What can I do now to get the phpDocumentor to work? Thanks.
  14. Hi, After following Larry's book and getting the helps from this forum, I finally get my first web project done. It has 4k product items and 1.5k users in the database. The website is fully functional in localhost. I carefully checked and killed all of bugs. Seems everything running without problem. So I need to looking into how to upload this project to the web host. I have never done anything like that before, so I am not sure what thing will go wrong and what things will screw up the project I have spent a year into. Please give some idea of what to avoid. I assume I just export the sql file from my local database and import it into web database with same name, and straightly upload all file in local host into web host. Change the BASE_URL value to web URL, and that will be all I need to do?
  15. Hi, Here the case is when user clicks a link, if he/she is not signed in yet, then he/she will be redirected to a login page. After the user successfully logged in, user should be redirected to the page url he/she intended to visit. I have no clue how to do this, but I found article online suggesting to store url into $_SESSION array before user has logged in. So I tried to store what url visitor clicked into $_SESSION['targetPage'], then redirect to login page. When user does a successful login, then $_SESSION ['targetPage'] is plugged into header function to redirect user back to the page intend. This method doesn't work, but I think the direction might be right. So please kindly give me some thought how to make this working. thank you very much! if(!isset($_SESSION['user_id'])){ // try storing the url that user clicked in $_SESSION $_SESSION['targetPage'] = $_SERVER['REQUEST_URI']; $url = 'login_page.php'; header("Location: $url"); exit(); } else { // save the session user id into $user_id $user_id = $_SESSION['user_id']; }
  16. Hello, I have been having trouble with this for quite some time I have tired to narrow it down the best I can. I able to complete the registration process, I went and check the sql database all fields have been filled. I think that the activation page cannot access the database to remove the active code. I tried to print or echo out the query value with echo "<p>Q: $q</p>" or print "<p>Q: $q</p>" all I see on the screen is "Q:" When I click the link from my email it doesn't seem to fail as it does not redirect me to index.php. I also do not get any error on my screen either. Any would help would be greatly appreciated. Regards Alex <div id="activate"> <?php /** * @author Alex Power * @copyright 2013 */ # Script 18.7 - activate.php require ('includes/config.inc.php'); $page_title='Activate Your Account'; if (isset($_GET['x'], $_GET['y']) && filter_var($trimmed['email'],FILTER_VALIDATE_EMAIL) && (STRlen($_GET['y']) == 32 )) { require (MYSQL); $q = "UPDATE users SET active=NULL WHERE (email='" . mysqli_real_escape_string($dbc, $_GET['x']) . "' AND active='" .mysqli_real_escape_sting($dbc, $_GET['y']) . "') LIMIT 1"; print "<p> Q: $q</p>"; $r = mysqli_query($dbc, $q) or trigger_error("Query:$q\n<br />)MySQL Error:" . mysqli_error($dbc)); if (mysqli_affected_rows($dbc)== 1 ) { echo "<h3>Your account is now active. You may now login.</h3>"; } else { echo '<p class="error">Your account could not be activated. Please re-check the link or contact the system administrator.</p>'; } mysqli_close($dbc); } else { //Redirect $url = BASE_URL . 'index.php'; ob_end_clean(); header("location:$url"); exit(); } // END of main IF-ELSE ?> </div>
  17. HI, again I tried to use the array looping technique from PHP advance book (chapter 1) on my project to output products category into <ul><li> list then apply superfish menu on them. But the output created extra <a>element which slightly messed up the superfish menu. I double check the make_list() function script and I can't tell why the extra <a> tabs are created. the code: <?php require ('includes/config.inc.php'); require (MYSQL); function make_list($parent) { global $cat_list; echo '<ul>'; foreach($parent as $catid => $c_list){ echo "<li>"; echo "<a href=\"index.php?cid=$catid\">"; echo $c_list; if(isset($cat_list[$catid])){ //$catid = parent_id make_list($cat_list[$catid]); } echo '</a></li>'; } echo '</ul>'; //close the ordered list } // end of make_list function $query = "SELECT cc.category_id, cc.parent_id, c.category FROM categories AS c INNER JOIN category_categories AS cc USING (category_id) WHERE c.publish = 1"; $result = mysqli_query($dbc, $query); if(!$result) echo mysqli_error($dbc); if(mysqli_num_rows($result)>=1){ $cat_list = []; while (list($c_id, $p_id, $cat) = mysqli_fetch_array($result, MYSQLI_NUM)){ $cat_list[$p_id][$c_id] = $cat; } } make_list($cat_list[0]); ?> the problem output(first few lines) <ul> <li> <a href="index.php?cid=1">Box Collection</a> <ul> <a href="index.php?cid=1"></a> <li> <a href="index.php?cid=1"></a> <a href="index.php?cid=32">Classic Preminum Brown Hardwood Boxes</a> </li> <li> <a href="index.php?cid=35">Hat Boxes</a> </li> <li> <a href="index.php?cid=36">Leatherette Boxes</a> </li> I expect the output to be: <ul> <li> <a href="index.php?cid=1">Box Collection</a> <ul> <li> <a href="index.php?cid=32">Classic Preminum Brown Hardwood Boxes</a> </li> <li> <a href="index.php?cid=35">Hat Boxes</a> </li> <li> <a href="index.php?cid=36">Leatherette Boxes</a> </li> From the make_list() function, which seems fine, I can't tell why the extra <a> is created. Please anyone can tell where is the problem?
  18. Hi, Larry In your Modern Javascript book, there is a dynamic select menu for picking operation system. Is that possible to create a similar menu in php? or manipulate that menu with php. I have 2 tables table 1: category contains category_id, category table 2: category_categories contains id, category_id, parent_id so I want to create a primary menu to have all categories that the parent_id equals to 0 (the top), when user select a category from primary menu, the subcategory menu become selectable and load the subcategory under the primary category that user has selected. Thank you all
  19. Hello, I tried to insert multiple image into image table using a foreach loop. The images insertion have returned no problem. But I wanted to catch the image_id of each insert and putted them into an array ($iid). Here is problem, no matter what I tried, the result always return 2 separated array: Array([0]=>9193) Array([1]=>9194). Is there anyway to solve this problem? I want Array([0]=>9193 [1]=>9194). Thank you all!. CODE: // query for media $query = 'INSERT INTO media (file_title, file_mimetype, file_type, file_url, file_url_thumb, file_is_product_image, created_on) VALUES (?,?,?,?,?,?,NOW())'; $stmt = mysqli_prepare($dbc, $query); $i = 0; foreach ($image_name as $key => $value){ $dot = strpos($value, '.'); $file_title = substr($value, 0, $dot); $extension = str_replace('.','',substr($value, $dot)); $file_mime = 'image/'.$extension; $file_type = 'product'; $file_url = $value; $file_url_thumb = 'images/product/resized/'.$file_title. $upload->getSuffix().$extension; $fipi = 1; mysqli_stmt_bind_param($stmt, 'sssssi', $file_title, $file_mime, $file_type, $file_url, $file_url_thumb, $fipi); mysqli_stmt_execute($stmt); // check result: if(mysqli_stmt_affected_rows($stmt) == 1){ // get the image id $iid = array(); $iid[$i++] = mysqli_stmt_insert_id($stmt); print_r($iid); // RESULT: Array([0]=>9193)Array([0]=>9194) } else { echo 'Insertion failed' . mysqli_stmt_error($stmt); } } // End of foreach
  20. Hi, I get a strange problem when I try to insert images data into media table. I decided to break down the problems section by sections. I rewrite the query using basic mysqli_query() function and insert one row at a time for testing purpose. Here is the strange thing, when I pass the value as variable into the VALUES, the insertion will fail and return an error: 'insertion failedUnknown column 'edvard' in 'field list''. However, If I just pass the string into VALUES(), the insertion goes without problem. I haven't run into this sort of problem before, can anyone explain the reason please. Thanks again! Failed Code: $file_title = 'edvard-much-the-scream'; $file_mime = '.jpg'; $product_type = 'product'; $file_url = 'edvard-much-the-scream.jpg'; $fipi = 1; $query = "INSERT INTO media (file_title) VALUES ($file_title)"; // this fails mysqli_query($dbc, $query); if(mysqli_affected_rows($dbc)==1){ $iid = mysqli_insert_id($dbc); echo $iid; } else { echo 'insertion failed' . mysqli_error($dbc); } Success Code: $file_title = 'edvard-much-the-scream'; $file_mime = '.jpg'; $product_type = 'product'; $file_url = 'edvard-much-the-scream.jpg'; $fipi = 1; $query = "INSERT INTO media (file_url) VALUES ('edvard-much-the-scream')"; // this works mysqli_query($dbc, $query); if(mysqli_affected_rows($dbc)==1){ $iid = mysqli_insert_id($dbc); echo $iid; } else { echo 'insertion failed' . mysqli_error($dbc); }
  21. Hello there, It's my first time asking question here, so I want to introduce myself a little bit. I was a graphic designer and 3D artist and I have never done any website except using iWeb. The company I work for needs to rebuild its website which has roughly four thousand products in the database. The website was built by hosting company using a open source CMS called OScommerce. My given project was to create a independent website using php and mysql that can be easily modified to suit the need when time is changing. When I receive the project around beginning of this year, I knew nothing about php and mysql so I went to amazon to buy 2 books. One was "PHP Solutions Dynamic Web Design Made Easy" and other one "Modern Javascript". I studied through both books. The PHP Solution is a good book, but not for absolute beginner. The way it organizes its content, mixing basic and advance concerts and methods together into one book keeps new learner confused and frustrated. So I wasn't really fully understand the material I have learned. As comparison, Modern Javascript is much clear to me and easy to learn. After finished Modern Javascript, I found Mr. Larry also wrote other php books, so I decided to pick up PHP and MySQL for Dynamic from Amazon. As I studied through (followed all examples), I found this book really helped me clear up the concert that I wasn't really clear of. So ends up, I purchased all php book from Larry and finished all of them. Now back to the question, I run into problem to insert timestamp into prepare statement, after some goolge search, there is answer in stackoverflowhttp://stackoverflow.com/questions/14096220/datetimes-now-function-does-not-work-with-pdo-mysql-prepared-statements I change my script according to it, but it returns an error: mysqli_stmt_bind_param(): Number of elements in type definition string doesn't match number of bind variables. I have no idea now, can anyone show me the right way to this please. Thanks. CODE: // query for products table $query = 'INSERT INTO products (product_sku, product_name, product_size, product_color, product_packaging, product_desc, created_on, new_arrival, feature, publish) VALUES (?,?,?,?,?,?,NOW(),?,?,?)'; $stmt = mysqli_prepare($dbc, $query); mysqli_stmt_bind_param($stmt,'ssssissiii', $sku,$name,$size,$color, $packaging,$desc, $new_arrival,$feature,$publish ); mysqli_stmt_execute($stmt);
  22. I just wanted to say a huge thanks to Larry for writing the book "PHP and MySQL for Dynamic Web Sites" (I have the 4th edition). To give a little history - I started using PHP about 10 years ago when I was asked to create a portal for some members of a small department that wanted to share information relating to health care. I initially looked at creating a static HTML site but soon came across PHPNuke. I know this particular CMS has had better days but for me 10 years ago it was revolutionary. I managed to set up a website and installed PHPNuke (including the database on MySQL). I was hooked from that point. However, I have become lazy over the years and although I have always wanted to create my own dynamic site, I have always stuck to using CMS/Portals (such as WordPress, Drupal, Joomla etc.) and never moved on. Now, don't get me wrong - these PHP based scripts are excellent and I will continue to use them but I have always just amended code within an already written script and never actually created a site of my own (from scratch) - although I would consider myself an intermediate PHP programmer (I use C# and .Net at work). Even after reading numerous books on the subject I still felt as though I was missing the glue that held everything together. I understood everything about XHTML, CSS, PHP, MYSQL, SESSIONS, COOKIES etc but could never join all the dots to make something work - so I was stuck in a sort of "head knowledge" state. That is changing now - thanks to the book above. This book is excellent and I am finally joining the dots and have a new found excitement for the language again. Thanks Larry - I don't know what makes your book so different and usable - but it is - and it's working. I have already purchased the Advanced book on the subject for the next stage of my journey. I look forward to updating you all on my progress. Thanks again :-)
  23. Hello, I am fairly new at php and mysql but finding the book very useful. I am having trouble with trying to register an account I fill out the registration form but when I click submit all I get is "Please enter your username" I am not getting any error appearing so I can not find out what the problem is. Here is my code I hope it is easy enough to read. I am also using a test server on 000webhost ("http://testwebserver.comli.com/register.php") I also have a localhost. <?php # register.php require('includes/config.inc.php'); $page_title = 'Register'; if ($_SERVER['REQUEST_METHOD'] == 'POST') { require (MYSQL); $trimmed = array_map('trim', $_POST); $un = $e = $p = FALSE; if (preg_match ('/^[A-z \' .-]{4,20} $/i', $trimmed['user_name'])) { $un = mysqli_real_escape_string ($dbc, $$trimmed['user_name']); } else { echo '<p class="error">Please enter your username! </p>'; } if (filter_var($trimmed['email'], FILTER_VALIDATE_EMAIL)) { $e = mysqli_real_escape_string ($dbc, $trimmed['email']); } else { echo '<p class="error>Please enter a valid email address! </p>'; } if (preg_match ('/^\w{4-20} $/', $trimmed['password1'])) { if ($trimmed['password1'] == $trimmed['password2']) { $p = mysqli_real_escape_string ($dbc, $trimmed ['password1']); } else { echo '<p class="error">Your password did not match the confirmed password!</p>'; } } else { '<p class="error">Please enter a vaild password!</p>'; } if ($un && $e && $p) { $q = "SELECT user_id From users WHERE user_name='$un', email='$e'"; $r = mysqli_query ($dbc,$q) or trigger_error("Query: $q\n<br />MYSQL Error:" . mysqli_error($dbc)); if (mysqli_num_rows($r) ==0) { $a = md5(uniqid(rand() , true)); $q = "INSERT INTO users (user_name, email, pass, active, reg_date) VALUES ('$e', '$un', SHA1('$p'), '$a', NOW())"; $r = mysqli_query ($dbc, $q) or trigger_error("Query: $q\n<br />MYSQL Error:". mysqli_error($dbc)); if (mysqli_affected_rows($dbc) == 1) { $body = "Thank you for reistering at PowerPlay. To activate your account, please click on this link:\n\n"; $body .= BASE_URL . 'activate.php?x='.urencode($e) . "&y=$a"; mail($trimmed['email'], 'Registration Confirmation', $body, 'From alexp2510@hotmail.com'); echo '<h3>Thank you for registering! A confirmation email has been sent to your email address. Please click on the link in order to activate your account.</h3>'; exit(); } else { // if it did not run OK. echo '<p class="error">You could not be registered due to a system error. we apologize for any inconvenience.</p>'; } } else { echo '<p class="error">That email address or username is already in use. If you have forgotten your password use the link at the right to have your password sent to you.</p>'; } } else { echo '<p class="error">Please try again.</p>'; } mysqli_close($dbc); } ?> <h1>Register</h1> <form action="register.php" method="POST"> <fieldset> <p><b>Username:</b> <input type="text" name="user_name" size="20" maxlength="20" value="<?php if (isset($trimmed['user_name'])) echo $_POST['user_name'];?>" /> </p> <p><b>Email Address:</b> <input type="text" name="email" size="30" maxlength="60" value="<?php if (isset($trimmed['email'])) echo $trimmed ['email']; ?>" /> </p> <p><b>Password:</b> <input type="password" name="password1" size="20" maxlength="20" value="<?php if (isset($trimmed['password1'])) echo $trimmed ['password1']; ?>" /> <small> Use only letters, numbers, and the underscore. <p>Must be between 4 and 20 characters long.</p></small></p> <p><b>Confirm Password:</b> <input type="password" name="password2" size="20" maxlength="20" value="<?php if (isset($trimmed['password2'])) echo $trimmed['password2']; ?>" /> </p> </fieldset> <div align="center"> <input type="submit" name="submit" value="Register" /></div> </form> Any help would be great. Thanks Alex
  24. My brain must be dead, because while I read the book, I am having trouble devising a solution to this problem. I would like to include a button on a page of query results that allows users to filter the results to those that match only certain criteria. I realize that it's not a good idea to run a whole new query just for this filtering, so I have been trying to look for a solution, but to no avail. Any tips? I'm sorry for being vague, I'd just rather not give away too much about the site's structure. Thank you!
  25. The most basic of questions .... how do I access the phpmyadmin dashboard (fig 4.8, p 120? I was initially able to get this dashboard using /localhost/phpmyadmin. I then set a root password in App. A in order to use MySQL Client. After that I wasn't able to get the phpmyadmin dashboard, getting the error shown in fig 4.9 on p121 instead, which referred me to App A to create a user. I did this. Created a user in Appendix A, and validated it, getting the blank screen shown in fig. A-15 on p. 599. But when I type in the URL of localhost/ phpmyadmin, I'm still getting fig 4.9. What am I missing?
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