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In the "Namespaces" section in Ch.6, Larry describes how the use keyword can allow us to reference a namespace once in our script so that we don't need to name the specific namespace over and over again when we make objects: Unfortunately, I am getting a class not found error when I try to use this. See program below, a shorter version of the type hinting example used earlier in the book. Company.php <?php namespace MyNamespace\Company; class Department{ private $_name; private $_employees; function __construct($name){ $this->_name = $name; $this->_employees = array(); }//__construct function addEmployee(Employee $e){ $this->_employees[] = $e; echo "<p>{$e->getName()} has been added to the {$this->_name} department.</p>"; }//addEmployee }//Department class Employee{ private $_name; function __construct($name){ $this->_name = $name; } function getName(){ return $this->_name; }//getName }//Employee ?> Using use in a separate file in the same directory as Company.php: <?php require('Company.php'); use MyNamespace\Company; $hr = new Department("Human Resources"); $e1 = new Employee("mary"); $hr->addEmployee($e1); ?> The code above generates a fatal error: "Fatal error: Class 'Department' not found" Am I missing something or am I not using use properly? Any assistance is greatly appreciated.

Page 211: [Tip] PHP allows you to more quickly reference namespaces...use keyword: Book says (incorrect): use MyNameSpace\Company; Should be (corrected): use MyNameSpace\Company\Department; use MyNameSpace\Company\Employee; All class names used must be included at the end of the namespace.