Instant Validation With Jquery $.Post

[Julia 2]

Hi,

 

I am having difficulty to have an instant validation carried out immediately after input of a value in a view file.

 

Here is the code (extract of the view file) that calls for the function (found in the controller file)

 

View file:

 

<?php Yii::app()->getClientScript()->registerScript('checkid2','$("#thisid").change(function()

{

alert("actiondupecheck");

$.post("index.php?r=roomtype/dupecheck", {thisid: $("#thisid").val()}, function(data) {

$("#dupecheck").html(data);

});

}

);');

?>

 

Controller file:

 

public function actionDupecheck()

{

$thisid = trim($_POST['thisid']);

$test =Piece::model()->find("id='$thisid'");

if(!empty($test)) {

echo sprintf("This id <strong>%s</strong>, exists already.", $thisid);

}

}

 

I have tried several ways but am completely stuck with this. I thought there was a problem with the syntax with the URL but after replacing 'dupecheck' with 'admin' in the view file, the admin function was called. What I am trying to do with this code, is to check for a duplicate entry in my table. I have been advised to use model validation rules. I will look into this suggestion but I also want to know that is wrong with my code. Thanks

[Antonio Conte 426]

jQuery is a JavaScript library that is client side. PHP and the $_POST array are server side. jQuery cannot validate the post array, that you'll have to do with PHP.

 

jQuery can grab IDs, classes and elements from a html page, thought. $(#id), $(.class), $(selector)

[Julia 2]

$.post initiates a POST request to the server...

[Antonio Conte 426]

Ah, sorry then. I'm no expert when it comes to jQuery. As I've never seen that before, I just thought you'd misunderstood something. Sorry.

[Julia 2]

You could be right though because I have been struggling with this code and can't get it to work According to my Jquery reference book, $.post is supposed to do that. Waiting for some help from this forum

[Edward 108]

If you have not done so already, it may worth posting here http://www.yiiframework.com/forum/.

 

There are occasion bugs in frameworks, so it would be worth asking about this on the yii forum also to see if anyone can help you.

[Edward 108]

Hi,

 

I am having difficulty to have an instant validation carried out immediately after input of a value in a view file.

 

Here is the code (extract of the view file) that calls for the function (found in the controller file)

 

View file:

 

<?php Yii::app()->getClientScript()->registerScript('checkid2','$("#thisid").change(function()

{

alert("actiondupecheck");

$.post("index.php?r=roomtype/dupecheck", {thisid: $("#thisid").val()}, function(data) {

$("#dupecheck").html(data);

});

}

);');

?>

 

Controller file:

 

public function actionDupecheck()

{

$thisid = trim($_POST['thisid']);

$test =Piece::model()->find("id='$thisid'");

if(!empty($test)) {

echo sprintf("This id <strong>%s</strong>, exists already.", $thisid);

}

}

 

I have tried several ways but am completely stuck with this. I thought there was a problem with the syntax with the URL but after replacing 'dupecheck' with 'admin' in the view file, the admin function was called. What I am trying to do with this code, is to check for a duplicate entry in my table. I have been advised to use model validation rules. I will look into this suggestion but I also want to know that is wrong with my code. Thanks

 

Actually i think i know the solution to this problem.

 

Okay you need to access your User Model the ActiveRecord, then just modify the rules, i will show some sample code where i have done this before:

 

public function rules()

{

// NOTE: you should only define rules for those attributes that

// will receive user inputs.

return array(

array('email, username, password', 'required'),

array('email, username, password', 'length', 'max'=>256),

array('email, username', 'unique'),

array('password', 'compare'),

array('password_repeat', 'safe'),

// The following rule is used by search().

// Please remove those attributes that should not be searched.

array('id, email, username, password last_login_time, create_user_id, update_time, update_user_id', 'safe', 'on'=>'search'),

);

}

 

So you see the part in the code array('email, username', 'unique') email and username have been declared as unique therefore only one email and username can occur in the model.

[Julia 2]

Thanks Edward for your suggestion. I have learnt something that I did not know even though it is not the solution to the problem. I sought the help of some people expert at PHP who found the solution to the problem. I had to modify the access rules of controller to give access to the required action that was being called in the URL parameter of Jquery $.post:

 

array('allow', // allow authenticated user to perform 'dupecheck' actions

'actions'=>array('dupecheck'),

'users'=> array('authorised username'),

 

 

That was a struggle!!

[Edward 108]

Glad to hear you found the solution, and thanks for posting it up here for us.