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Hey guys. I need help with the program. I get error Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in C:\xampp\htdocs\index.php on line 15

Here is my code: 

1st file.

<?php
    include_once 'includes/DuombazesInfo.php'
?>

<!DOCTYPE html>
<html>
<head>
    <title></title>
</head>
<body>

<?php
    $sql = "SELECT * FROM vartotojai";
    $result = mysqli_query($con, $sql);
    $resultCheck = mysqli_num_rows($result);

    if ($resultCheck > 0) {
        while ($row = mysqli_fetch_assoc($result)) {
            echo $row['vartotojas_vardas'];
        }
    }
?>

</body>
</html>

2nd file.

<?php

$dbServername = "localhost";
$dbUsername = "root";
$dbPassword = "";
$dbName = "duombaze";

$con = mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbPassword);

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23 minutes ago, tautuxs9 said:

Hey guys. I need help with the program. I get error Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in C:\xampp\htdocs\index.php on line 15

Here is my code: 

1st file.

<?php
    include_once 'includes/DuombazesInfo.php'
?>

<!DOCTYPE html>
<html>
<head>
    <title></title>
</head>
<body>

<?php
    $sql = "SELECT * FROM vartotojai";
    $result = mysqli_query($con, $sql);
    $resultCheck = mysqli_num_rows($result);

    if ($resultCheck > 0) {
        while ($row = mysqli_fetch_assoc($result)) {
            echo $row['vartotojas_vardas'];
        }
    }
?>

</body>
</html>

2nd file.

<?php

$dbServername = "localhost";
$dbUsername = "root";
$dbPassword = "";
$dbName = "duombaze";

$con = mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbPassword);

 

23 minutes ago, tautuxs9 said:

Hey guys. I need help with the program. I get error Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in C:\xampp\htdocs\index.php on line 15

Here is my code: 

1st file.

<?php
    include_once 'includes/DuombazesInfo.php'
?>

<!DOCTYPE html>
<html>
<head>
    <title></title>
</head>
<body>

<?php
    $sql = "SELECT * FROM vartotojai";
    $result = mysqli_query($con, $sql);
    $resultCheck = mysqli_num_rows($result);

    if ($resultCheck > 0) {
        while ($row = mysqli_fetch_assoc($result)) {
            echo $row['vartotojas_vardas'];
        }
    }
?>

</body>
</html>

2nd file.

<?php

$dbServername = "localhost";
$dbUsername = "root";
$dbPassword = "";
$dbName = "duombaze";

$con = mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbPassword);

Don't need no more. Fixed myself

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This happens when there's an error with your query (i.e., it causes a MySQL error; it doesn't return 0 or more results). You should apply the standard MySQL debugging techniques: print out the query and run it using another interface or just invoke mysqli_error() directly. 

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