tonyscarpelli
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Posts posted by tonyscarpelli
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I can step through Javascript using Chrome or FireFox, but can't seem to find any way to do that with PHP.
Is it possible to step through PHP code?
Thanks.
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The code is in the Xampp server on my machine. Isn't that supposed to work? If it doesn't, then Xammp is not working.
I am running the code from within NoteTab which calls the browser with the URL of the server.
Maybe that is how I shouldn't be doing it?
I'll try putting it on my web site and see how that works.
Thanks.
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I used the Chapter 11 book code last week in Xampp after installing Xampp and it worked.
This week I tried it out and it didn't work.
I rebooted and removed IIS which was on my computer, but that didn't work either.
After doing a bit of debugging, it turned out that the Ajax status code was 0.
I changed the test.js code so that it worked with a status = 0 ( || (ajax.status == 0) ). And now it works again.
So what whould make the status code turn into 0 from last week?
Or, in other words, what makes the ajax status equal 0 to begin with?
Confusing...
Thanks.
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Thanks HartleySan, I installed Xampp and worked my way through some install errors, but got it to work.
I put the Ajax Test book code into the server and got it to work.
I have a question about this, however.
Do you guys edit your code outside Xampp and copy the code into it?
Or do you edit the code inside the Xampp server?
Thanks.
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I jumped to the Ajax chapter since I needed to understand it in some other projects.
I entered in the code from the book and I can't get it to work.
I tried the downloaded code from the book site, and that didn't work either.
Do I have to put this code in my web site or can I run it from my loacal PC?
Thanks.
Chapter 9, Script 9.7, Password.Php Dup Password
in PHP and MySQL for Dynamic Web Sites: Visual QuickPro Guide (4th Edition)
Posted
If I entered the same new password as the old password, an error occurred that didn't inform the user of this. The following code can be changed as needed. CU
I added the following code that checks for duplicate old and new passwords:
//-------------------------------------------------------------------------
// Check to see if password the same
$q = "SELECT user_id FROM users WHERE (email='$e' AND pass=SHA1('$np') )";
$r = @mysqli_query($dbc, $q);
$num = @mysqli_num_rows($r);
if ($num == 1) {
//echo 'Not OK' . ' ' . $num; // for testing.
$errors[] = 'Your new password is the same as your old password.';
}
//-------------------------------------------------------------------------
if (empty($errors)) { // If everything's OK.