[Selected Suburb Not Displaying Correctly]

When I run the following code it runs through the entire list of suburbs and only displays the last one rather than the selceted suburb.

 

What am I doing wrong?

 

 

<?php
 $query="select * from tblStaff where StaffID=$staffID";
$result=@mysqli_query($dbc,$query);
$row=mysqli_fetch_array($result,MYSQLI_ASSOC);

$selected_suburb=$row['Suburb'];

echo"<label>Suburb</label><br />";
echo"<select name=\"Suburb\">";
$query="select suburb_id, suburb, state, postcode
from tblPostcodes
order by suburb,state, postcode asc;";
$result=@mysqli_query($dbc,$query);
while($row=mysqli_fetch_array($result,MYSQLI_ASSOC)){
 	 $selected="";
 	 foreach($row as $suburb_id => $suburb){
 	 if($row['suburb_id']==$selected_suburb){
 	 $selected="selected";
 	 }
 echo"<option value={$row['suburb_id']}
 selected=$selected>
 {$row['suburb']} {$row['state']} {$row['postcode']}</option>";
 	 }
}
echo"</select>";
?>

[Making Radio Buttons Sticky]

Thank you.

This works very well.

[Making Radio Buttons Sticky]

Sorry, code should read:

<?php
$Available=1;
echo "<label>Currently Available?</label><br />
     <input type=\"radio\" name=\"Available\" 
            value=(if($Available==1){echo'checked=\"checked\"'})>Yes
     <input type=\"radio\" name=\"Available\" 
            value=(if($Available!=1){echo'checked=\"checked\"'})>No";
?>

[Making Radio Buttons Sticky]

<p><p>What is wrong with this code?

<?php
$Available=1;
...
<label>Currently Available?</label><br />
<input type=\"radio\" name=\"Available\" value=(if($Available==1){echo'checked=\"checked\"'})>Yes
<input type=\"radio\" name=\"Available\" value=(if($Available!=1){echo'checked=\"checked\"'})>No
?>

 

Whatever I do I cannot get any value to display in either option.