slimpundit Posted December 30, 2011 Share Posted December 30, 2011 I'm working through chapter 13 now. I just finished the listing quotes and editing quotes sections on pages 396-403. I've added the ...is_administrator function. I'm signed into my computer (windows 7) as the administrator but the error message pops up for both view quotes and edit quotes saying access is denied. If i'm the administrator, why am i not getting access to these pages? I checked the control panel settings to verify that I am signed on as administrator. If anyone could help, I'd appreciate it. Link to comment Share on other sites More sharing options...
Larry Posted December 30, 2011 Share Posted December 30, 2011 The is_administrator() function has nothing whatsoever to do with your Windows 7 account. That PHP function checks for a site administrator, which is verified by logging in through the site. Link to comment Share on other sites More sharing options...
slimpundit Posted December 30, 2011 Author Share Posted December 30, 2011 Larry, Somehow, I knew this would be an easy fix. Logged in and it works fine. I've tried to work with some other books but didn't get much out of them. This book is great! I've recommended it to my class and will continue working through the entire series. Thanks for the book(s) and the website. They have both been really helpful. Slim Link to comment Share on other sites More sharing options...
Larry Posted December 30, 2011 Share Posted December 30, 2011 Thank you very much, Slim, for the nice words. Are you an instructor or a student? And where? Link to comment Share on other sites More sharing options...
slimpundit Posted January 1, 2012 Author Share Posted January 1, 2012 Larry, I'm a student at the College of Southern Nevada. Just finished up my AAS in web design and will continue studying CS at UNLV in the fall of 2012. I took a class that emphasized php and javascript and had to do a project. This book is the only reason that I was able to complete my project. Slim Link to comment Share on other sites More sharing options...
Larry Posted January 2, 2012 Share Posted January 2, 2012 Excellent. Thanks again for the nice words and good luck with your studies! Link to comment Share on other sites More sharing options...
kir Posted June 10, 2014 Share Posted June 10, 2014 Ok, I can not log in on my own site? I have access premitted for user (myself) on go daddy data base? I can sign in under me@example.com password testpass. Here's my code: <?php /* This page lets people log into the site. */ // Set tow variable with default values: $loggedin = false; $error = false; //Check if the form has been submitted: if ($_SERVER['REQUEST_METHOD'] == 'POST') { // Handle for form: if (!empty($_POST['email']) && !empty($_POST['password'])) { if ( (strtolower($_POST['email']) == 'me@example.com') && ($_POST['password'] == 'testpass') ) { // Correct! // Create the cookie setcookie('Sade', 'Adu', time()+3600); // Indicate they are logged in: $loggedin = true; }else{ // Incorrect! $error = 'The submitted email address and password do not match those on file!'; } }else{ // Forgot a field. $error = 'Please make sure you enter both an email address and a passoword!'; } } // Set the page title and include the header file: define('TITLE', 'Login'); include('template/header.html'); // Print an error if one exist if ($error) { print '<p class="error">' . $error . '</p>'; } // Indicate the user is logged in, or show the form: if ($loggedin) { print '<p>You are now logged in!</p>'; }else{ print '<h2>Login Form</h2> <form action="login.php" method="post"> <p><label>Email Address <input type="text" name="email" /></label></p> <p><label>Password<input type="password" name="password" /></label></p> <p><input type="submit" name="submit" value="Log In!" /></p></form>'; } include('template/footer.html'); // Need the footer ?> Link to comment Share on other sites More sharing options...
kir Posted June 11, 2014 Share Posted June 11, 2014 I need help, please. My database and tables and created. I can not login as administrator and I can't figure out how to. I can't view add or edit a quote because I am not the administrator. I have tried everything I know. I am showing that my cookies are created. Link to comment Share on other sites More sharing options...
Larry Posted June 12, 2014 Share Posted June 12, 2014 That exact code only allows me@example.com/testpass to login. It doesn't use a database. It doesn't have administrators. Link to comment Share on other sites More sharing options...
kir Posted June 12, 2014 Share Posted June 12, 2014 So, if I change that code to my email and password I would still only be able to log in as a user and not as an admin. How do I log in as an admin, Lar? I've gone over everything a million times but can't figure it out. Link to comment Share on other sites More sharing options...
mogosselin Posted June 13, 2014 Share Posted June 13, 2014 You see this line: if ( (strtolower($_POST['email']) == 'me@example.com') && ($_POST['password'] == 'testpass') ) It says : If the input field named "email" contains me@example.com AND the input field named "password" contains "testpass", create cookie and set the variable $testpass = true The $_POST['email'] array will be set to whatever field named "email" is posted from the form. Same thing with the $_POST['password']. so if you have an input field like this: <input type="text" name="email">, well the $_POST['email'] will contains the value entered in that field. Now, there's nothing accessing a database in the code you posted, so changing anything in any database won't have any effect on how the code you pasted here works. But, if you change the line with the hardcoded email and password to whatever you want, yes, it'll work. Link to comment Share on other sites More sharing options...
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